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zysi [14]
3 years ago
15

(2/7)power 7 divided (2/7)power 5

Mathematics
2 answers:
lesantik [10]3 years ago
8 0

Answer:

4/49

Step-by-step explanation:

\frac{ (\frac{2}{7})^{7}  }{( \frac{2}{7} )^{5} }  = ({ \frac{2}{7} )}^{7 - 5}  \\  = ( \frac{2}{7})^{2}  \\  =  \frac{4}{49}

Harrizon [31]3 years ago
6 0

Answer:

4/49

Step-by-step explanation:

7-5 = 2

2/7*2/7 = 4/49

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Answer:

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3 years ago
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Which table represents a function? A 2-column table with 4 rows. The first column is labeled x with entries negative 3, 0, negat
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Answer:

This is a many-to-one function as the value of y = -1 corresponds to two values of x:

\begin{array}{|c|c|}\cline{1-2} x & y\\\cline{1-2} -3 & -1\\\cline{1-2} 0 & 0\\\cline{1-2} -2 & -1\\\cline{1-2} 8 & 1\\\cline{1-2}\end{array}

Step-by-step explanation:

<u>Function</u>

A special relationship where each input (x-value) has a single output (y-value).

A function is <u>one-to-one</u> if each value in the range (y-values) corresponds to exactly one value in the domain (x-values).

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This is a many-to-one function as the value of y = -1 corresponds to two values of x:

\begin{array}{|c|c|}\cline{1-2} x & y\\\cline{1-2} -3 & -1\\\cline{1-2} 0 & 0\\\cline{1-2} -2 & -1\\\cline{1-2} 8 & 1\\\cline{1-2}\end{array}

This is not a function as the value of x = -5 corresponds to two values of y:

\begin{array}{|c|c|}\cline{1-2} x & y\\\cline{1-2} -5 & -5\\\cline{1-2} 0 & 0\\\cline{1-2} -5 & 5\\\cline{1-2} 6 & -6\\\cline{1-2}\end{array}

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\begin{array}{|c|c|}\cline{1-2} x & y\\\cline{1-2} -4 & 8\\\cline{1-2} -2 & 2\\\cline{1-2} -2 & 4\\\cline{1-2} 0 & 2\\\cline{1-2}\end{array}

This is not a function as the value of x = -4 corresponds to two values of y:

\begin{array}{|c|c|}\cline{1-2} x & y\\\cline{1-2} -4 & 2\\\cline{1-2} 3 & 5\\\cline{1-2} 1 & 3\\\cline{1-2} -4 & 0\\\cline{1-2}\end{array}

8 0
2 years ago
Please help me the answers with an x next to them are wrong, and it’s not the other way around please help!!
MissTica

Answer:

its sayin the rectangle answer plus on so

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Step-by-step explanation:

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Neporo4naja [7]
<span>C=2(3.14)r 
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