Ask question

Ask question

All categories

3 years ago

8

During the school year, each student planted 2 x 10^2 trees as part of a community service project. If there are 3.5 x 10^3 stud

ents in the school, how many trees did they plant in total?

1 answer:

amm18123 years ago

4 0

Answer:

Total number of trees planted = $7\times 10^{5}$ trees

Step-by-step explanation:

Trees planted by each student = $2\times 10^2$

Total number of students = $3.5\times 10^3$

Using unitary method to find total number of trees planted by all the students in school.

1 student plants = $2\times 10^2$ trees

$3.5\times 10^3$ student would plant = $(2\times 10^2)\times (3.5\times 10^3)$

We apply the product rule of exponents to multiply $[a^xa^y=a^{x+y}]$

⇒ $(2\times 3.5)\times(10^2\times 10^3)$

⇒ $7\times 10^{2+3}$

⇒ $7\times 10^{5}$ trees

Total number of trees planted = $7\times 10^{5}$ trees

You might be interested in

How may shells does Joshua have?

Tpy6a [65]

24, since 54-30 is 24, and 30+24 is 54.

5 0

3 years ago

Read 2 more answers

Find the missing dimension of a parallelogram a=84.77in b=17.3 in what is the height

zavuch27 [327]

Answer:

Step-by-step explanation:

a

8 0

3 years ago

I need help.. i really want to go sleep.. thank you so much...

Effectus [21]

Answer:

1) True 2) False

Step-by-step explanation:

1) Given $\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}$

To verify that the above equality is true or false:

Now find $\sum\limits_{k=0}^8\frac{1}{k+3}$

Expanding the summation we get

$\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{0+3}+\frac{1}{1+3}+\frac{1}{2+3}+\frac{1}{3+3}+\frac{1}{4+3}+\frac{1}{5+3}+\frac{1}{6+3}+\frac{1}{7+3}+\frac{1}{8+3}$ $\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}$

Now find $\sum\limits_{i=3}^{11}\frac{1}{i}$

Expanding the summation we get

$\sum\limits_{i=3}^{11}\frac{1}{i}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}$

Comparing the two series we get,

$\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}$ so the given equality is true.

2) Given $\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\sum\limits_{i=1}^3\frac{3i}{i+5}$

Verify the above equality is true or false

Now find $\sum\limits_{k=0}^4\frac{3k+3}{k+6}$

Expanding the summation we get

$\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3(0)+3}{0+6}+\frac{3(1)+3}{1+6}+\frac{3(2)+3}{2+6}+\frac{3(3)+4}{3+6}+\frac{3(4)+3}{4+6}$

$\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}+\frac{12}{8}+\frac{15}{10}$

now find $\sum\limits_{i=1}^3\frac{3i}{i+5}$

Expanding the summation we get

$\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3(0)}{0+5}+\frac{3(1)}{1+5}+\frac{3(2)}{2+5}+\frac{3(3)}{3+5}$

$\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}$

Comparing the series we get that the given equality is false.

ie, $\sum\limits_{k=0}^4\frac{3k+3}{k+6}\neq\sum\limits_{i=1}^3\frac{3i}{i+5}$

6 0

3 years ago

Solve the system by elimination. State whether the system has one solution, infinite solutions, or no solution.

lukranit [14]

I'm not sure I'm right, I'm not all that good at elimination but I think the answer is y = 13. So I guess the answer would be A. one solution

4 0

3 years ago

Read 2 more answers

An object is thrown upward at a speed of 124 feet per second by a machine from a height of 19 feet off the ground. The height h

klasskru [66]

a) For this question we set h=59 and solve for t, in order to do so we use the general formula for second-degree equations:

$\begin{gathered} t=\frac{-124\pm\sqrt[]{124^2-4(-16)(-40)}}{2(-16)} \\ t=\frac{-124\pm113.21}{-32} \end{gathered}$

The height of the object will be 59 feet at t=7.41 seconds and t=0.34 seconds.

b) When the object reaches the ground, h=0 therefore:

$0=-16t^{2}+124t+19$

Solving for t we get:

$\begin{gathered} t=\frac{-124\pm\sqrt[]{124^2-4(-16)(19)}}{2(-16)} \\ t=\frac{-124\pm\sqrt[]{16592}}{-32}=\frac{-124\pm128.81}{-32} \end{gathered}$

Therefore, since t cannot be negative the solution is t=7.9 seconds.

7 0

1 year ago