<span>-31=-6z-4z
Subtract 4z from -6z
-31=-10z
Divide both sides by -10
Final Answer: 3.1 or 3 1/10</span>
Answer:
I) |xz| ≈ 28.6 km
II) |yz| ≈ 34.8 km
Step-by-step explanation:
Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)
|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°
Using Trigonometric ratio - SOHCAHTOA
I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20
|xz| = 20 * Tan 55 = 20 * 1.428
|xz| = 28.56 km
|xz| ≈ <u>28.6 km</u>
<u />
II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|
|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°
|yz| = 20 ÷ 0.574 = 34.84 km
|yz| ≈ <u>34.8 km</u>
I believe the equation should be set up like this: 85 + 5x + 5x + 5x - 10 + 5x + 5 = 540. Don't forget to combine like terms! Please let me know by sending me a message if you need any more help :)
Given
GO.o has 3 orange picks for every 2 green
there are 25 picks in all
Find out how many picks are orange.
To proof
As given in question
GO.o has 3 orange picks for every 2 green
i.e the ratio of orange to every green becomes

total number of picks = 25
let the GO.o pick of 3 orange picks for every 2 green =x
than the equation becomes
3x + 2x = 25
5x = 25
x = 5
Than
the number of oranges = 3x
putting the value of x
= 15
the number of green = 2x
= 10
thus the 15 picks are orange.
Hence proved
Answer:
2nd Quadrant
Step-by-step explanation:
Points on 2nd quadrant 
As we plot the point
we can see that it lies in the 2nd Quadrant.