A composite figure is created using a square and a triangle. What is the area of the figure?

Please help me i will really appreciate it .

Ahat [919]

9514 1404 393

Answer:

slope = 2

Step-by-step explanation:

See the attachment for the markup.

It is usually convenient to choose places where the graph crosses grid intersections. Here, the graph crosses the x- and y-axes at integer values, so those points could be used, for example. We chose points away from the axes so that the rise and run lines could be seen more easily.

The graph has a rise/run of ...

slope = rise/run = 2/1 = 2

The slope of the line is 2.

7 0

3 years ago

In parallelogram LMNO, what is the measure of angle N? 50° 70° 110° 130°

belka [17]

we know that

In a parallelogram opposite angles are congruent and consecutive angles are supplementary.

So

m∠O=m∠M

m∠L=m∠N

m∠O+m∠L= $180$

Step $1$

Find the value of x

$(x+20)+(2x+10)=180\\ 3x+30=180\\ 3x=180-30\\ x=\frac{150}{3} \\ \\ x=50\ degrees$

Step $2$

Find the value of angle L

m∠L $=(2x+10)$

m∠L $=(2*50+10)$

m∠L $=110\ degrees$

Remember that

m∠N=m∠L

m∠N= $110\ degrees$

therefore

the answer is

the measure of the angle N is equal to $110\ degrees$

4 0

3 years ago

Read 2 more answers

Jeremy drew a polygon with four right angles and four sides with the same length name all the polygons that he have done

erik [133]

The most-specific name for such a polygon is square.

It can also be called a rectangle, rhombus, parallelogram, or quadrilateral.

6 0

3 years ago

Use an angle sum identity to derive each double-angle identity.

Simora [160]

$\ [cos(2\theta)]'=(2cos^2\theta-1)'=2(cos^2\theta)'-(1)'\\\\=2\cdot2cos\theta\cdot(-sin\theta)-0=-2\cdot2sin\theta cos\theta=\boxed{-2sin2\theta}\\\\Used:\\\ [f(x)-g(x)]'=f'(x)-g'(x)\\\{f[g(x)]\}'=f'[g(x)]\cdot g'(x)\\(cosx)'=-sinx\\sin2x=2sinxcosx$