Question

Triangle ABC is translated on the coordinate plane below to create triangle A'B'C'.

Answer 1

Step 1

Find the rule of the translation

we know that

$A(-1,-2) \\A'(-4,4)$

so

the rule of the translation is

$(x,y)-----> (x+3,y+6)$

that means

the translation is $3$ units to the right and $6$ units up  

Step 2

Find the coordinates of the ordered pair of point H'

$H(1,3)$

Applying the rule of the translation

$H(x,y)----->H'(x+3,y+6)$

$H(1,3)----->H'(1+3,3+6)$

$H(1,3)----->H'(4,9)$

therefore

the answer is

$H'(4,9)$

Answer 2

As ypu can see, point A is moved by [3, 6], so point H=(1, 3) would turn into H'=(1, 3)+[3, 6]=(4, 9).