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3 years ago

Can some one help me with this question.

Mathematics

2 answers:

antoniya [11.8K]3 years ago

8 0

Area of the small circle = $\pi$ r $x^{2}$ = 3.14 x 7 $x^{2}$ = 153.86

Area of the big circle = $\pi$ R $x^{2}$ =3.14 x 14 $x^{2}$ = 615.44

The shaded area = area of the big circle - area of 2 small circle = 615.44-2x153.84≅308

The answer is 308

creativ13 [48]3 years ago

6 0

So the small circles are touching each other and they have a radius of 7 inches. so that means that the big circle will have a radius of 14 inches which is double the small circles radius. after we find the radius of the big circle, we have to calculate the big circles area. which we will find by the formula

$14 \times 14 \times \pi$
14 squared times pi is 615.44
this is the big circles are but the question askes the area left after we subtract the 2 small circles
we find the are of the small circles by doing
$7 \times 7 \times \pi$
which is 153.86.
after finding the area of the small circles we multiply it by two a d subtract it from the big circles area
$615.44 - 153.86 \times 2$

and we find 307.72 which is the closest to 308
so the answer is D

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Help me with this one problem please :( Find the following arc measures.

r-ruslan [8.4K]

Answer:

Arc KL $=23$

Arc OM $=113$

Step-by-step explanation:

We know that Angle NPM is equal to 90 degrees.

Therefore, Angle KPM is also equal to 90 degrees.

We are told that Arc LM is equal to 67.

Thus, the measure for Arc KL is equal to $90-67=23$

We also know that Angle OPN is equal to Angle KPL.

Therefore, the measure of Arc ON $=23$

Using that information, we know that Arc OM is equal to $90+23=113$

Hope I helped!

3 0

3 years ago

If 14x = ^13√14, what value of x makes this equation true?

Andrews [41]

The value of x is 1/13 (4th choice)

Step-by-step explanation:

${a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} }$

If 14^x = ¹³√14, what value of x makes this equation true?

$\sqrt[13]{14} = {14}^{x} \\ \sqrt[13]{14} = {14}^{ \frac{1}{13} }$

So, the value of x is 1/13 (4th choice)

Hope it helpful and useful :)

6 0

3 years ago

Please help me Show your work 10 points

Svet_ta [14]

<h2>Answer</h2>

After the dilation $\frac{5}{3}$ around the center of dilation (2, -2), our triangle will have coordinates:

$R'=(2,3)$

$S'=(2,-2)$

$T'=(-3,-2)$

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

$(x,y)$ → $(x-2, y+2)$

Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor $\frac{5}{3}$ . Therefore our second partial rule will be:

$(x,y)$ → $\frac{5}{3} (x-2,y+2)$

$(x,y)$ → $(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )$

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

$(x,y)$ → $(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)$