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Luba_88 [7]
3 years ago
10

Find the area of the irregular figure.

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
7 0

Answer:

a

Step-by-step explanation:

PilotLPTM [1.2K]3 years ago
6 0

Answer:

Option A. 432\ units^{2}

Step-by-step explanation:

we know that

The area of the irregular figure is equal to the area of two trapezoids

The area of trapezoid is equal to

A=\frac{1}{2}(b1+b2)h

where

b1,b2 are the parallel bases

h is the perpendicular distance between the parallel bases

<u>Find the left trapezoid area</u>

A1=\frac{1}{2}(4+25)(16)=232\ units^{2}

<u>Find the trapezoid area on the right</u>

A2=\frac{1}{2}(25+15)(10)=200\ units^{2}

The area of the irregular figure is

A=A1+A2=232\ units^{2}+200\ units^{2}=432\ units^{2}

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The length and width of the fence should be made 76.25 feet and 23.75 feet respectively. Also, the expression for the length is L = 3W + 5 and the perimeter is P = 2(4W + 5).

<h3>How to determine the fence's dimension?</h3>

Mathematically, the perimeter of a rectangle can be calculated by using this formula;

P = 2(L + W)

<u>Where:</u>

  • P is the perimeter of a rectangle.
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Since the length of this fence is 5 more than 3 times the width, we have:

L = 3W + 5

Substituting the given parameters into the formula, we have;

200 = 2(3W + 5 + W)

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200 = 8W + 10

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W = 23.75 feet.

For the length, we have:

L = 3W + 5

L = 3(23.75) + 5

L = 76.25 feet.

Read more on perimeter of a rectangle here: brainly.com/question/17107023

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