All categories

3 years ago

Find the area of the irregular figure.

Mathematics

2 answers:

Lera25 [3.4K]3 years ago

7 0

Answer:

Step-by-step explanation:

PilotLPTM [1.2K]3 years ago

6 0

Answer:

Option A. $432\ units^{2}$

Step-by-step explanation:

we know that

The area of the irregular figure is equal to the area of two trapezoids

The area of trapezoid is equal to

$A=\frac{1}{2}(b1+b2)h$

where

b1,b2 are the parallel bases

h is the perpendicular distance between the parallel bases

<u>Find the left trapezoid area</u>

$A1=\frac{1}{2}(4+25)(16)=232\ units^{2}$

<u>Find the trapezoid area on the right</u>

$A2=\frac{1}{2}(25+15)(10)=200\ units^{2}$

The area of the irregular figure is

$A=A1+A2=232\ units^{2}+200\ units^{2}=432\ units^{2}$

You might be interested in

4.(-x 4 + 13x 5 + 6x 3 ) + (6x 3 + 5x 5 + 7x4)

grigory [225]

Answer:

140

Step-by-step explanation:

=(-4+55+18)+(18+25+28)

=69+71

=140

3 0

3 years ago

Find the surface area of the composite solid.

Westkost [7]

We have:

4 triangles with the base b = 5ft and the height h = 6ft

4 rectangles with the lenght l = 5ft and the width w = 4ft

1 square with side a = 5ft.

The formula of an area of a riangle:

$A_T=\dfrac{1}{2}bh$

Substitute:

$A_T=\dfrac{1}{2}(5)(6)=\dfrac{1}{2}(30)=15\ ft^2$

The formula of an area of a rectangle:

$A_R=lw$

Substitute:

$A_R=(5)(4)=20\ ft^2$

The formula of an area of a square:

$A_S=a^2$

Substitute:

$A_S=5^2=25\ ft^2$

The Surface Area of composite solid:

$SA=4A_T+4A_R+A_S$

Substitute:

$SA=4(15)+4(20)+25=60+80+25=165\ ft^2$

<h3>Answer: The Surface Area of the composite solid is 165 ft².</h3>

3 0

3 years ago

Being timed please help

Dafna1 [17]

Number 4 is arithmetic explicit

Number 1 is arithmetic recursive

Number 2 is geometric explicit

Number 3 isgeometric recursive

6 0

2 years ago

HELLLPPPP ASAPP!!!!!!!!!!!! WILL GIVE BRAINLIEST!

DanielleElmas [232]

Solution is in the attachment.

(-3, 5, 6)

8 0

3 years ago

|×|=×<br>is the absolute value of x always, sometimes, or never x

il63 [147K]

Answer:

Sometimes

Step-by-step explanation:

I’ll give you an example so you can understand:

Let’s say x is 4. So plug 4 into the problem:

|4|=4 → This is a very true statement, where the absolute value of 4 is equal to 4.

Now, let’s say x is -7. So plug -7 into the problem:

|-7|=-7 → This is a false statement because it’s saying that the absolute value of -7 is -7 which is very untrue.

So |x|=x only works for positive numbers, but not negative numbers. Therefore, |x|=x is the absolute value of x <u>sometimes.</u>

<u />

Hope this helps and answers your question! :)

6 0

3 years ago