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3 years ago

1/3(n 4)=9 how do you work this problem out

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

4 0

1/3(n4)=9
I assume that it's a multiplication between n and 4
then solving the equation
4n= 9/1/3
4n= 27
n=27/4=6.75

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Four pounds of almonds cost $30, 7 pounds of almonds cost $52.50, and

erma4kov [3.2K]

The second one or y = 7.50x

That is because the four pounds of almonds divided by thirty dollars is 7.50. So if you were to add one more pound of almonds, you would have to pay $7.50 more.

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3 years ago

2x - 2y = 6 3x + 2y = 9 Solve the system of equations. A) x = 0, y = 3 B) x = 3, y = 0 C) x = 1, y = -2 D) x = -2, y = 1 3) x +

nadezda [96]

Answer:

B) x = 3, y = 0

Step-by-step explanation:

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3 years ago

Another triangle congruent question , it’s in the picture thanks :)

neonofarm [45]

Answer:

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Step-by-step explanation:

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3 years ago

A department store surveyed 428 shoppers, and the following information was obtained: 216 shoppers made a purchase, and 294 were

Maurinko [17]

Answer:

(a) 169

(b) 341

(d) 87

Step-by-step explanation:

Consider the Venn diagram below.

The total number of shoppers surveyed is, N = 428.

Number of shoppers who made a purchase, n (P) = 216

Number of shoppers who were satisfied with the service they received,

n (S) = 294

Number of shoppers who made a purchase but were not satisfied with the service, $n(S^{c}\cap P)$ = 47

(a)

The number of shoppers who made a purchase and were satisfied with the service = n (S ∩ P)

$n(S\cap P)=n(P)-n(S^{c}\cap P)\\=216-47\\=169$

(b)

The numbers of shoppers who made a purchase or were satisfied with the service = n (P ∪ S)

$n(P\cup S)=n(P)+n(S)-n(P\cap S)\\=n(P)+n(S)-n(S\cap P)\\=216+294-169\\=341$

(c)

The numbers of shoppers who were satisfied with the service but did not make a purchase = $n(S\cap P^{c})$

$n (S\cap P^{c} ) = n (S) - n (S \cap P)\\=294-169\\=125$

(d)

The number of shoppers who were not satisfied and did not make a purchase = $n(S^{c}\cap P^{c})$

$n(S^{c}\cap P^{c})=N-n(S\cup P)\\=N-n(P\cup S)\\=428-341\\=87$

6 0

3 years ago

Aaron is designing a party game in which he needs exactly 24 possible outcomes. Which sets of actions can he use to have a stati

zlopas [31]

Answer:

Counting from the top:

fist option

fourth option

fifth option.

Step-by-step explanation:

Any set that has a multiplicative outcome, such that the total number of outcomes is 24.

Remember that if we have a combination of two events, one with N outcomes and the other with M outcomes, the total number of outcomes is:

M*N

This is the main thing we need to see.

Let's analyze each option:

1) flip a coin (2 outcomes)

flip a coin again (2 outcomes)

roll a 6 sided dice ( 6 outcomes)

total number of outcomes:

2*2*6 = 24

2) Selecting a number from 1 to 16 (16 outcomes) and rolling a dice of 8 sides (8 outcomes).

The total number of outcomes is:

8*16 = 128

We wanted only 24.

3) Selecting a number from the set {1, 3, 5, 7, 9} (5 outcomes)

flip a coin (2 outcomes)

flip the coin again (2 outcomes)

total number of outcomes:

2*2*5 = 20

We wanted 24, we can discard this.

4) Spin the thing (3 outcomes)

roll an 8-sided dice (8 outcomes)

Total number of outcomes:

8*3 = 24

This is a correct option.

5) Select a card from A to D (4 outcomes)

Roll the thing (6 outcomes)

total number of outcomes:

6*4 = 24

This is a correct option.

6) Select a card from A to N {14 options}

Roll the thing once (10 outcomes)

Total number of outcomes:

14*10 = 140

We wanted 24, so we can discard this option.

Then the correct options are:

first one, fourth one, and fifth one.

8 0

3 years ago