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3 years ago

Given the set of integers one through 12 what is the probability choosing an odd number or a number greater than nine

Mathematics

1 answer:

snow_lady [41]3 years ago

7 0

Answer:

1/4

Step-by-step explanation:

the numbers greater than nine are: 10,11,12

1,3,5,7,9

So that is nine numbers

9/12 can be simplified to 3/4 if you divide by 3

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A right triangle has a hypotenuse length of 12, and one side length of 9. find the missing side length. do the side lengths form

Rina8888 [55]

Use the Pythagorean theorem:

$a^2+b^2=c^2$

c - a hypotenuse

a, b - legs

We have: a = 9 and c = 12. Substitute:

$9^2+b^2=12^2$

$81+b^2=144$ <em>subtract 81 from both sides</em>

$b^2=63\to b=\sqrt{63}\\\\b=\sqrt{9\cdot7}\\\\b=\sqrt9\cdot\sqrt7\\\\ \boxed{b=3\sqrt{7}}$

A Pythagorean triple consists of three positive integers a, b and c, such that

$a^2+b^2=c^2$ .

$b=3\sqrt{7}$ is not positive integer.

<h3>The sides of the triangle do not form a pythagorean triple.</h3>

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3 years ago

I need help with this question

SVEN [57.7K]

It is c. Because the original slope is -3 and perpendicular is opposite. So the perp slope is 1/3. C is the answer.

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3 years ago

Example 2: Combining Use of the Multiplication and Addition Rules

bulgar [2K]

Answer:

The probability of getting 6's on both cubes is $\frac{1}{36}$ .

The probability that the total score is at least 11 is $\frac{1}{12}$ .

Step-by-step explanation:

Consider the provided information.

A red cube has faces labeled 1 through 6, and a blue cube has faces labeled in the same way.

Part (A) Both cubes show 6’s.

Probability of getting 6 on red cube is $\frac{1}{6}$

Probability of getting 6 on blue cube is $\frac{1}{6}$

Thus, the probability of getting 6's on both cubes is:

$P(\text{Both 6's})=\frac{1}{6}\times\frac{1}{6}=\frac{1}{36}$

Hence, the probability of getting 6's on both cubes is $\frac{1}{36}$ .

Part (B) The total score is at least 11.

The possible number of outcomes in which total score is at least 11 is:

Red shows 6 and Blue shows 5.

Blue shows 6 and Red shows 5.

Blue shows 6 and Red shows 6.

Thus, the probability of total score is at least 11.

$P(\text{Total is at least 11})=\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}\\P(\text{Total is at least 11})=\frac{1}{12}$

Hence, the probability that the total score is at least 11 is $\frac{1}{12}$ .

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3 years ago

Solve for x 2|x-6|+14=38

ale4655 [162]

Answer:

x=18 x=-6

Step-by-step explanation:

2|x-6|+14=38

The first step is to isolate the absolute value

Subtract 14 from each side

2|x-6|+14-14=38-14

2|x-6|=24

Divide by 2 on each side

2/2|x-6|=24/2

|x-6| = 12

Now we can seperate the absolute value into two parts, the positive and the negative

x-6 =12 x-6 = -12

Add 6 to each side

x-6+6 =12+6 x-6+6 = -12+6

x=18 x= -6

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3 years ago

13. Which fraction is halfway between 3/5 and<br>5/7?

Hitman42 [59]

18/35 is halfway between 3/5 and 5/7. Do you want me to explain or just the answer?

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3 years ago

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