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3 years ago

Given the set of integers one through 12 what is the probability choosing an odd number or a number greater than nine

Mathematics

1 answer:

snow_lady [41]3 years ago

7 0

Answer:

1/4

Step-by-step explanation:

the numbers greater than nine are: 10,11,12

1,3,5,7,9

So that is nine numbers

9/12 can be simplified to 3/4 if you divide by 3

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I need help with number 5 please.

amid [387]

The answer to number 5 is 1/4 of a foot. there are 12 inches in a foot. 12 divided by 4 is 3. So 12 inches divided by 4 sections is 3 inches in each section.

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3 years ago

The equation 7×+1=4×+10 ?

HACTEHA [7]

7x-4x=10-1
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4 years ago

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Determine if the statement is true or false. If a linear system has the same number of equations and variables, then it must hav

lutik1710 [3]

Answer:

False

Step-by-step explanation:

Consider the equations with the same number of equations and variables as shown below,

$x_{1} + x_{2} = 0\\x_{1} + x_{2} = 1$

This equation has no solution because it is not possible to have two numbers that give a sum of 0 and 1 simultaneously.

$x_{1} + x_{2} = 1\\2x_{1} + 2x_{2} = 2$

This equation has infinitely many possible solutions.

Therefore it is FALSE to say a linear system with the same number of equations and variables, must have a unique solution.

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3 years ago

What is the simplified form of 357-5672

spayn [35]

Answer:

17/2

Step-by-step explanation:

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3 years ago

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Suppose that Ayumi rolls a pair of fair six-sided dice. Let A be the event that the first die lands on 2 and B be the event that

Tanya [424]

Answer:

$\frac{1}{6} ,\frac{1}{6} ,\frac{1}{36}\,,\,independent$

Step-by-step explanation:

Given: Let A be the event that the first die lands on 2 and B be the event that the second die lands on 2.

To find:

P(A), the probability that the first die lands on 2

P(B), the probability that the second die lands on 2

P(A and B): the probability that the first die lands on 2 and the second die lands on 2

Solution:

Probability refers to chances of occurrence of some event.

Probability = number of favourable outcomes/total number of outcomes

Sample space = $\left \{ 1,2,3,4,5,6 \right \}$

Total number of outcomes = 6

For P(A):

Number of favourable outcomes = 1

So,

$P(A)=\frac{1}{6}$

For P(B):

Number of favourable outcomes = 1

So,

$P(B)=\frac{1}{6}$

P(A and B) = $P(A)P(B)=\left ( \frac{1}{6} \right )\left ( \frac{1}{6} \right )=\frac{1}{36}$

Yes, A and B are independent events as happening of each of the event does not depend on the other.

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3 years ago