Step-by-step explanation:
I'll just give you 2 examples if you need a better understanding tell me
1) 2 * 2/4
a. First make 2 --> 2/1 so it's a fraction
b. Multiply 2 by 2 giving you 4
c. Multiply 1 by 4 giving you 4
d. You'll get 4/4
e. Simplify to 1 by dividing by the numerator and denominator 4
Answer : 1
2) 3 * 4/6
a. First make 3 --> 3/1 so it's a fraction
b. Multiply 3 by 4 giving you 12
c. Multiple 1 by 6 giving you 6
d. You'll get 12/6
e. Simiply to 2 by dividing the numerator and denominator by 6
Answer : 2
Answer:
Option (C)
Step-by-step explanation:
From the map attached,
Area of the rectangular yard = length × width
Length of the yard = 10 units
Width of the yard = 8 units
Area = 10 × 8
= 80 square yards
Since, pool is a composite figure of two rectangles,
Therefore, area of the pool = Area of large segment + Area of the small pool
= (5 × 6) + (3 × 3)
= 30 + 9
= 39 square units
Ratio of Area of the pool and area of yard = 
Therefore, Option (C) will be the answer.
If one gallon is 21 miles, simply multiply 21 by five, for each of the five gallons and it is approximately 105 miles using 5 gallons of gas.
Answer:
77
Step-by-step explanation:
3.5(11)+1.9(11)+1.6(11)
3.5(11)=38.5
1.9(11)=20.9
1.6(11)=17.6
38.5+20.9+17.6
77
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
