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barxatty [35]
2 years ago
8

Which function has a domain​

Mathematics
1 answer:
Novosadov [1.4K]2 years ago
5 0

Answer:

F(x) = - \sqrt[3]{x}  

Step-by-step explanation:

A square root can only have a positive input for the domain

(The domain is the input for the function)

The cube root can be either negative or positive as an input

F(x) = - \sqrt[3]{x}  can have inputs from negative infinity to infinity

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i do not know sorry for that Step-by-step explanation:

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top one

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Read 2 more answers
Find the domain of the function y = 3 tan(2/3x)
Damm [24]

Answer:

{x∈R | \frac{2x}{3\pi } +\frac{1}{2}, x∉Z}

Step-by-step explanation:

Given the function y=3tan(2/3x)

We know that tangent is a function that's continuous within it's domain but not continuous on all real numbers

Also, the roots of y=3tan(2/3x) is 3\pi n/2 where n is an integer

Note that the domain of the function cannot be within 3\pi n/2

Therefore, {x∈R | \frac{2x}{3\pi } +\frac{1}{2}, x∉Z}

5 0
2 years ago
What is 358,062 rounded to the nearest thousand
posledela
358,062 rounded to the nearest thousand is 358,00

6 0
3 years ago
Find the work required to move an object in the force field F = e^x + y (1, 1, z) along the straight line from A(0, 0, 0) to B(-
DENIUS [597]

\vec F(x,y,z)=(e^x+y)(1,1,z)

is conservative if we can find a scalar function f such that \nabla f=\vec F. This would require

f_x=e^x+y

f_y=e^x+y

f_z=(e^x+y)z

Integrating both sides of the first equation wrt x gives

f(x,y,z)=e^x+xy+g(y,z)

Differentiating both sides of this wrt y gives

f_y=x+g_y=1\implies g_y=1-x\implies g(y,z)=y-xy+h(z)

but we assumed g was a function of y and z, independent of x. So there is no such f and \vec F is not conservative.

To find the work, first parameterize the path (call it C) by

\vec r(t)=(1-t)(0,0,0)+t(-4,5,-5)=(-4t,5t,-5t)

for 0\le t\le1. Then

\vec r'(t)=(-4,5,-5)

and the work is given by the line integral,

W=\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^1(e^{-4t}+5t,e^{-4t}+5t,-(e^{-4t}+5t)5t)\cdot(-4,5,-5)\,\mathrm dt

W=\displaystyle\int_0^1(125t^2+5t+(25t+1)e^{-4t})\,\mathrm dt=\boxed{\frac{2207}{48}-\frac{129}{16e^4}}

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3 years ago
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