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tensa zangetsu [6.8K]
3 years ago
12

Diego’s deductible is $500. If he breaks his arm and needs it set, it costs $5000. What percentage of this cost does his company

pay for?
Mathematics
1 answer:
elena-s [515]3 years ago
3 0
The answer is ten percent
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Find the 21st term in the arithmetic sequence.<br> 3, 7, 11, 15, 19, ...
NNADVOKAT [17]

The 21st term of the given arithmetic sequence is 83. The nth term of an arithmetic sequence is applied to find the required value where n = 21.

<h3>What is the nth term of an arithmetic series?</h3>

The nth term of an arithmetic sequence is calculated by the formula

aₙ = a + (n - 1) · d

Here the first term is 'a' and the common difference is 'd'.

<h3>Calculation:</h3>

The given sequence is an arithmetic sequence.

3, 7, 11, 15, 19, ....

So, the first term in the sequence is a = 3 and the common difference between the terms of the given sequence is d = 7 - 3 = 4.

Thus, the required 21st term in the sequence is

a₂₁ = 3 + (21 - 1) × 4

⇒ a₂₁ = 3 + 20 × 4

⇒ a₂₁  = 3 + 80

∴ a₂₁  = 83

So, the 21st term in the given arithmetic sequence is 83.

Learn more about the arithmetic sequence here:

brainly.com/question/6561461

#SPJ1

5 0
1 year ago
Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to
ra1l [238]

Answer:

The  confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

  The  sample size is n = 41

   

For a 95% confidence the level of significance is  \alpha  = [100 - 95]\% =  0.05 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }=  1.96

For a 90% confidence the level of significance is  \alpha  = [100 - 90]\% =  0.10 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }=  1.645

So we see with decreasing confidence level the critical value  decrease

Now the margin of error is mathematically represented as

         E =  Z_{\frac{\alpha }{2} } *  \frac{s}{\sqrt{n} }

given that other values are constant and only Z_{\frac{\alpha }{2} } is varying we have that

         E\ \  \alpha \ \   Z_{\frac{\alpha }{2} }

Hence for  reducing confidence level the margin of error will be reducing

  The  confidence interval is mathematically represented as

        \= x  - E  <  \mu <  \= x  + E

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value  reduces, the margin of error  reduces and the confidence interval becomes narrower

3 0
3 years ago
1000 jumps in 3 hours. How many jumps are there per hour?
DiKsa [7]
Just multiply 1000 jumps by 3 to get your answer.
6 0
3 years ago
Read 2 more answers
What is the next number in the pattern?
forsale [732]

Answer:

9

Step-by-step explanation:

3 3/4= 3.75.

3.75-2=1.75

1.75+5.5=7.25 or 7 1/4

7.25+1.75=9

5 0
3 years ago
Read 2 more answers
The line is given by equation y–1.5x = c. What is the value of c if the line passes through the point K (2, –3).
aleksandr82 [10.1K]

Answer:

c = -6

Step-by-step explanation:

To find the value of c to make the line pass through the point K = (2, -3), we just need to use the values of x = 2 and y = -3 in the equation, then we find the value of c.

So, we have that:

y - 1.5*x = c

(-3) - 1.5 * (2) = c

-3 - 3 = c

c = -6

So the value of c is -6

To check if the value is correct, we can use the value x = 2 and see if the value of y is -3:

y - 1.5*x = -6

y - 1.5*2 = -6

y - 3 = -6

y = -6 + 3 = -3

So it's correct.

7 0
3 years ago
Read 2 more answers
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