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pashok25 [27]
3 years ago
9

Solve for the probability that a student is selected at random from a group of 20 students will draw a 6 from a bag with the num

bers 1 though 15 in it. Show and explain all of your work.
Mathematics
1 answer:
Mariana [72]3 years ago
8 0
Depending on what the number is in for the bag
You might be interested in
If f(x) = (4x-3)^2, then f(-2)=?<br> A: -121<br> B: -22<br> C: 22<br> D: 25<br> E: 121
SOVA2 [1]
The answer is E. 121.
7 0
3 years ago
Select the two values of x that are roots of this equation.<br> 2x2 + 11x - 6 = 0
sukhopar [10]

Answer:

2×2 +11x - 6 =0

4 + 11x - 6 = 0

11x - 6 =4

-6 + 4 = 11x

-2 = 11x

X =11/2

X =5.2

8 0
3 years ago
3. Si al doble de un número se le resta su mitad resulta 30. ¿Cuál es el número? Plantear ecuación y resolverla
guajiro [1.7K]

Respuesta:

2x - 0.5x = 30

x = 20

Explicación paso a paso:

Llamemos "x" a la incógnita, el número desconocido.

Cuando nos referimos al doble de un número, es lo mismo que 2x.

Cuando nos referimos a la mitad de un número, es lo mismo que 0.5 x.

Consideremos que al doble de un número (2x) se le resta su mitad 0.5x) y se obtiene 30. La ecuación resultante es:

2x - 0.5x = 30

1.5x = 30

x = 30/1.5 = 20

8 0
3 years ago
(50 points and brainliest.Need help ASAP)
Aleksandr-060686 [28]

Answer:  " 2x (2x - 1) (x + 1) " .

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Step-by-step explanation:

______________________________________

Given:  

  f(x)   =  9x³ + 2x² − 5x  + 4  ;

  g(x)  =  5x³ − 7x + 4 ;

______________________________________

What is:  f(x) − g(x) ?

______________________________________

Plug in:  " 9x³ + 2x² − 5x + 4 "  for:  " f(x) " ;

    and:   " (5x³ − 7x + 4) " ;  for:  "g(x)" ;

______________________________________

→  " f(x) − g(x)   =  

   

       " 9x³ + 2x² − 5x + 4  − (5x³ − 7x + 4) "  .

______________________________________

Rewrite this expression as:

 →  " 9x³ + 2x² − 5x + 4  − 1(5x³ − 7x + 4) "  .

 →   {since:  " 1 " ;  multiplied by "any value" ;  is equal to that same value.}.

______________________________________

Now, let us example the following portion of the expression:

______________________________________

 "  − 1(5x³ − 7x + 4) "

_____________________________________

Note the "distributive property"  of multiplication:

______________________________________

    →   a(b + c) = ab + ac ;

______________________________________

Likewise:

     →  a(b + c + d) = ab + ac + ad .

______________________________________

As such:

______________________________________

    →  "  − 1(5x³ − 7x + 4)  "  ;

______________________________________

             =   (-1 * 5x³) + (-1 * 7x) + (-1 * 4) ;

             =  - 5x³  +  (-7x)  +  (-4)  ;

             =   - 5x³  − 7x − 4  ;

_____________________________________

Now, add the "beginning portion of the expression" ; that is:

  " f(x) " ;  to the expression ;  which is:

                        →   9x³ + 2x² − 5x  +  4  ;

 →  as follows:  

_______________________________________

 →  9x³ + 2x² − 5x  +  4 − 5x³ − 7x − 4  ;

 →  {Note that the:  " - " sign; that is;

       the "negative sign", in the term:  " -5x³ " ;

       becomes a: " − " sign; that is; a "minus sign" .}.

______________________________________

Now, combine the "like terms" of this expression; as follows:

  + 9x³  −  5x³  =  + 4x³ ;

 − 5x − 7x  =  − 2x ;

 + 4 − 4 = 0 ;

______________________________________

and we have:

______________________________________

 →     " 4x³  +  2x²  − 2x ".

______________________________________

Now, to write this answer in "factored form" :

Note that among all 3 (three) terms in this expression, each term has a factor of "2" .  The lowest coefficient among these 3 (three) terms is "2" ;  so we can "factor out" a "2".  

Also, each of the 3 (three) terms in this fraction is a coefficient to a variable.  That variable takes the form of "x".  The term in this expression  with the variable, "x";  with the lowest degree has the variable: "x" (i.e. "x¹ = x" ) ;  so we can "factor out a "2x" (rather than just the number, "2".).

So, by factoring out a "2x" ;  take the first term [among the 3 (three) terms in the expression] —which is:  "4x³ " .

2x * (?)  = 4x³  ?  ;'

↔  \frac{4x^3}{2x} = ? ;

→  4/2 = 2 ;

\frac{x^{3}}{x} = \frac{x^3}{x^1}  = x^{(3-1)} =  x^{2} ;  

As such:   2x * (2x²)  =  4x³ ;

___________________________________________

Now, by factoring out a "2x" ;  take the second term [among the 3 (three) terms in the expression] — which is:  "2x² " .

2x * (?) = 2x²  ? ;

↔   \frac{2x^{2}}{2x} =  ?

→  2/2 = 1 ;

→  \frac{x^{2}}{x} = \frac{x^2}{x^1}= x^{(2-1)} } = x^1 = x ;

As such:  2x * (x) = 2x²

__________________________________________

Now, by factoring out a "2x" ;  take the third term [among the 3 (three) terms in the expression] — which is:  " − 2x " .

2x * (?) =  - 2x ;

↔  \frac{-2x}{2x} = -1 ;

As such:  2x * (-1) =  − 2x .  

__________________________________________

So:

__________________________________________

Given the simplified expression:

 →     " 4x³  +  2x²  − 2x " ;

We can "factor out' a:  " 2x " ;  and write the this answer is: "factored form" ; as:

__________________________________________

  "2x (2x²  +  x  −  1 ) . "

Now, we can further factor the:

    " (2x²  +  x  −  1) " ; portion;

Note:  "(2x² + x - 1)" =

2x² + 2x - 1x -1 = (2x -1) + x (2x - 1 ) =

(2x - 1)  ( x + 1)

_______________________________________

Now, bring down the "2x" ; and write the Full "factored form" ; as follows:

_______________________________________

    →   " 2x (2x - 1) (x + 1) "  .

_______________________________________

Hope this helps!

 Wishing you the best!

_______________________________________

7 0
3 years ago
Last year your school had 1200 students enrolled, this year your school has135% of that amount enrolled. how many students are e
iren2701 [21]
1200 = 100%
35% of 1200 = 420
1200 + 420 = 1620

There are 1620 students enrolled this year.
7 0
3 years ago
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