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Gekata [30.6K]
4 years ago
15

I need help please.

Mathematics
2 answers:
Lelu [443]4 years ago
8 0

Answer:

7

Step-by-step explanation:

Replace the variations with given values: z = 9 and y = 6

\frac{ {z}^{2} - 3y }{z}  \\   \frac{ {9}^{2} - 3 \times 6 }{9}  =  \frac{81 - 18} {9}  \\  \frac{63}{9}  = 7

Lera25 [3.4K]4 years ago
8 0

Answer:

7

Step-by-step explanation:

substitute the variables

\frac{9^{2}-3(6) }{9}

\frac{81-18}{9}

\frac{63}{9}

= 7

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