Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
Answer:
8. 1 is the answer.
Step-by-step explanation:
<h3>
#Bonjour</h3>
Answer:non statistical
Step-by-step explanation:
b ≤ 9 (b is less than or equal to 9)
Hope this helps! ;)