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3 years ago

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The linear scale factor of two similar solids is given. Then the surface area and volume of the smaller figure are also given. F

ind the surface area and volume of the large figure.
Scale factor: 1:8

Surface area: 6

volume: 18

Surface area: ?

volume: ?

1 answer:

katen-ka-za [31]3 years ago

4 0

Answer:

SA:48 V:144

Step-by-step explanation:

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Item 8 Solve for x. Use the quadratic formula. 2x2−5x−9=0 Enter the solutions, in simplified radical form, in the boxes.

Lubov Fominskaja [6]

Answer:

5+√97/4

Also 5-√97/4

Step-by-step explanation:

The Quadratic formula is x=-b+-√b^2-4ac/2a

This means that we should plug the values for A B AND C into the formula

We can work out that

<u><em>A = 2</em></u>

<u><em>B=-5</em></u>

<u><em>C=-9</em></u>

Once we have put these into the formula we get

5+√97/4 (all over 4) aka 3.71

Also 5-√97/4 (all over 4) aka -1.21

7 0

3 years ago

Read 2 more answers

Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen

Jobisdone [24]

Parameterize $S$ by the vector function

$\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k$

so that the normal vector to $S$ is given by

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}$

In this case, the normal vector is

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k$

with magnitude $\sqrt{1^2+2^2+1^2}=\sqrt6$ . The integral of $f(x,y,z)=e^z$ over $S$ is then

$\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx$

where $T$ is the region in the $x,y$ plane over which $S$ is defined. In this case, it's the triangle in the plane $z=0$ which we can capture with $0\le x\le8$ and $0\le y\le\frac{8-x}2$ , so that we have

$\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}$

5 0

3 years ago

hich equation represents a line that passes through (5, 1) and has a slope of ? y – 5 = (x –1) y – = 5(x –1) y – 1 = (x –5) y –

gtnhenbr [62]

Answer:

The equation that would represent it would be y - 1 = (x - 5)

Step-by-step explanation:

In order to get this, we can start with the base form of point-slope form.

y - y1 = m(x - x1)

Now put the point in for (x1, y1)

y - 1 = (x - 5)

3 0

3 years ago

You are playing a game in which a single die is rolled. If a 2 or 5 comes up, you win $36, otherwise you lose $36. What is your

ozzi

Your expected value is 36*2/6 + -36*4/6, which is equal to $-12.

7 0

3 years ago

Look at the image, HELP PLEASE.

Wittaler [7]

Answer:

1/2

Step-by-step explanation:

Well, First let us find the amount of numbers in a die greater than 3.

Remember greater than 3 does not include 3.

We have 3 numbers, 4,5,6 that are greater than 3.

The probabilty of getting a rolling a number greater than 3 is 3/6.

The probability of the coin landing on heads is 1/2.

BUT, the problem is only requiring for you to find the probabilty of rolling a dice greater than 3. (key words)

Which is 3/6 or simplified to 1/2.

6 0

3 years ago