V=xyz where x,y,z are the three dimensions...
V=(1 4/5)(1 4/5)1
V=(9/5)(9/5)=81/25
V=3 6/25 ft^3
Answer:
a° = 58°
b° = 48°
c = 74°
d° = 122°
Step-by-step explanation:
<em>Angles on a straight line add up to 180°</em>
58° + d° = 180°
d° = 180° - 58° = 122°
<em>Alternate angles are equal.</em>
a° = 58°
<em>Angles in a triangle add up to 180°.</em>
48° + 58° + c° = 180°
106° + c° = 180°
c° = 180° - 106° = 74°
<em>Angles on a straight line add up to 180°</em>
74° + 58° + b° = 180°
132° + b° = 180°
b° = 180° - 132° = 48°
Answer:
304m^2
Step-by-step explanation:
First find the surface area of the base by multiplying the length by the width.
(12m) (8m)= 96m^2
Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.
1/2 (12m) (10m)= 60m^2
Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.
1/2 (8m) (11m)= 44m^2
Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.
base=a, front/ back triangles= b, side triangles=c
SA= a + 2b +2c or SA= a +b +b +c +c
Using one of the equations above solve for the total surface area.
SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)
or
SA= (96m^2) + 2(60m^2) +2(44m^2)
SA= (96m^2) +(120m^2) +(88m^2)
SA= 304m^2
Given:
In an office, there are 75 women and 125 men.
To find:
The ratio of the number of men to the number of women.
Solution:
We have,
Number of men = 125
Number of women = 75
The ratio of the number of men to the number of women is:




Therefore, the ratio of the number of men to the number of women is 5:3.
Answer:
qfgjwtjywkshlshlwykqtj
Step-by-step explanation:
htjyjwjwk4o47orjluothjfrh5qi6woi623o76woeluhsmgsmfanegruq2yiwyjajgafbrhqtj26iwykw5jqrhrhqqrhq5uq5u14uqtjtqjtqjatiatiatiFUFJfbatabtnafbaFJfutjfjbffbafbafjaafjagjqrhqrjafbf r rhaafjfjafabr atanathbra r r rbbb3rhb qtwhwtjwgjwtjqtjqfb hqtjqfbqfb afbqfhqfhafjwtjukdb sg b th2tj h1rhf b rttt r r rbrbrbrvr rvr r r ecscsgj