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Sunny_sXe [5.5K]
3 years ago
5

Whats the product of 22 and 39?

Mathematics
2 answers:
8090 [49]3 years ago
8 0

You can set up the problem vertically like this

 22

x

 39

In which after solving the problem the answer would be 858

MArishka [77]3 years ago
4 0
858 is the answer I hope
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Help me plz u will make my day
oksian1 [2.3K]

Answer:

18 1/3. You add 18 1/3 to cancel out that number.

Step-by-step explanation:

5 0
3 years ago
a banana contains 105 calories.last week,brendan and lea ate a total of 14 bananas.how many calories does this represent?
Crank
Well if they ate a total of 14 bananas and each banana is 105 calories, that means that you have to multiply 105 calories by 14 bananas. The answer is 1470 calories.
8 0
3 years ago
Read 2 more answers
A General Motors buyer-incentive program offered a 5.5% rebate on the selling price of a new car. What rebate (in dollars) would
Mashcka [7]

Answer: he would receive a rebate of $1677.5

Step-by-step explanation:

A General Motors buyer-incentive program offered a 5.5% rebate on the selling price of a new car. This means that if the selling price of the new car is $x, the rebate (in dollars) that a customer would receive is

5.5/100 × x = 0.055 × x = 0.055x

Therefore, for a customer who purchased a $30,500 car under this program, the rebate that he would receive is

0.055 × 30500 = $1677.5

6 0
4 years ago
FIND NTH TERM QUICKEST IN GETS BRAINLIEST
patriot [66]
Answer is 13 because the numbers are increasing though odd numbers that are also increasing if that makes sense.

It’s going from 4 > 9 > 16 > 25 > 36

so from 4-9 it adds 5 and from 9-16 it adds 7 and goes on so that’s it’s like

+5 > +7 > +9 > +11

sorry if it doesn’t make good sense
4 0
3 years ago
find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the large
katrin2010 [14]

A generic odd number can be written as

2k+1,\quad k \in \mathbb{Z}

Since there is an odd number every two numbers, three consecutive odd numbers will be

2k+1,\quad 2k+3,\quad 2k+5

Now let's make up the equations: the sum of the first two is

(2k+1)+(2k+3)

And 27 less than 3 times the largest is

3(2k+5)-27

These two must be the same, so we have

(2k+1)+(2k+3)=3(2k+5)-27 \iff 4k+4 = 6k+30-27 \iff 4k+4=6k+3

Subtracting 4k and 3 from both sides gives

1=2k \iff k=\dfrac{1}{2}

Which means that the problem has no solution.

To confirm this hypothesis, we can observe that, on the left hand side, we have the sum of two odd numbers, which is even

On the right hand side, we have an odd number, multiplied by 3 (still odd), take away 27 (still odd).

So, the left hand side is even, and the right hand side is odd. They can't be the same number.

7 0
4 years ago
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