Please simplifu.....
2 answers:
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Answer:
D
Step-by-step explanation:
Recall that the area of a triangle is given by:
In this case, the base is <em>x</em> and the height is <em>y</em>. Hence:
We can write the following ratios:
Solve for <em>x</em> and <em>y</em>:
Substitute:
And simplify. Hence:
In conclusion, our answer is D.
Answer:
See figure attached and explanation below.
Step-by-step explanation:
For this case we have the following dataset given:
0.74, 0.32, 1.66, 3.59, 4.55, 6.47, 9.99, 0.7, 0.37, 0.76, 1.9, 1.77, 2.42, 1.09, 2.03, 2.69,2.41, 0.54, 8.32, 5.70, 0.75, 1.96, 3.36, 4.06, 12.48
And for this case we can use the followinf R code to create the frequency histogram.
> x<-c(0.74, 0.32, 1.66, 3.59, 4.55, 6.47, 9.99,0.7, 0.37, 0.76, 1.9, 1.77, 2.42, 1.09, 2.03, 2.69,2.41, 0.54, 8.32, 5.70, 0.75, 1.96, 3.36, 4.06,12.48)
> length(x)
[1] 25
> hist(x, prob=TRUE)
And for this case we have the histogram on the figure attached. For the number of classes we use the formula of sturges:
And for this case we have approximately 6 classes. And that's what we can see on the figure attached
As we can see most of the values are on the left so then we have a right skewed to the right and the distribution is assymetrical, with most of the values between 0 and 6
