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Elenna [48]
3 years ago
15

Please simplifu.....

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
5 0
Your answer is going to be B
iris [78.8K]3 years ago
3 0

Answer:

B) 2a√15a

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers. 2a√15a

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|5x|+5=45<br><br> can you explain this absloute value equation <br> i have a midterm
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So first, you get the absolute value to one side:
|5x|+5=45\\&#10;|5x|=40

Next, set up two equations; One where the value inside the absolute value lines is positive, and another where it is negative, and solve both for the variable:
|5x|=40\\5x=40\\x=\frac{40}{5}=8\\\\-5x=40\\x=\frac{40}{-5}=-8

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3 years ago
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What is the answer in the remainder
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Answer:

12 with a remainder of 5

Step-by-step explanation:

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2 years ago
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liberstina [14]

Answer:

Step-by-step explanation:

abc = 1

We have to prove that,

\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1

We take left hand side of the given equation and solve it,

\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}

Since, abc = 1,

\frac{1}{c}=ab and c = \frac{1}{ab}

By substituting these values in the expression,

\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}=\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+ab}+\frac{1}{1+\frac{1}{ab}+\frac{1}{a}}

                                       =\frac{b}{b+ab+1}+\frac{1}{1+b+ab}+\frac{ab}{ab+1+b}

                                       =\frac{1+b+ab}{1+b+ab}

                                       =1

Which equal to the right hand side of the equation.

Hence, \frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1

5 0
3 years ago
What is the answer?
taurus [48]

x^2y^3(1-x^3y)

This is because you can at most, factor out x² and y³

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