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3 years ago

What does NO3 stand for in nitrate

1 answer:

5 0

Inorganic or organic ester or salt of nitric acid, containing the (NO3-) ion. Nitrates are the most water soluble of all salts, and play a major part in nitrogen cycle and nitratepollution. Inorganic nitrates are formed by bacteria and are an essential component of agricultural soil.

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A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,

agasfer [191]

Answer:The answer is C on edge!

Explanation:

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3 years ago

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What is the chemical reaction for respiration

Verdich [7]

Respiration is the chemical process by which organic compounds release energy. The compounds change into different ones by exergonic reactions. The hydrolysis of adenosine triphosphate (ATP) to adenosine diphosphate (ADP) and phosphoric acid (Pi) releases energy (it is an exergonic reaction).

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3 years ago

A 5 g sample of pure gold has a density of 19.3 g/ml. Your friend purchased a gold ring that was made of 25 g of pure gold. What

patriot [66]

Answer:

96.5 g/ml

Explanation:

If 5g is 19.3 then 25g is 19.3x5 which is 96.5 g/ml

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3 years ago

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Trichloroacetic acid (CCl3CO2H) is a corrosive acid that is used to precipitate proteins. The pH of a 0.050-M solution of trichl

Nataly [62]

Answer:

Ka = 0.16

Explanation:

HClO₄ is a strong acid and it will dissociate completely to give hydrogen ion and the conjugate base.

The pH of HClO₄ will be calculated as:

pH = -log[H⁺]

pH = -log[0.04] = 1.4

The trichloroacetic acid is a weak acid and it will not dissociate completely.

The dissociation will be:

$CCl_{3}COOH---> CCl_{3}COO^{-} + H^{+}$

Initial 0.05 0 0

Change -x +x +x

Equilibrium 0.05-x x x

Ka = $\frac{[H^{+}][ClO_{4}^{-}]}{[HClO_{4}]}$

As pH of the acid = 1.4 it means the concentration of hydrogen ion is 0.04.

Therefore

x = 0.04

Putting values

Ka = $\frac{(0.04)(0.04)}{0.05-0.04}=0.16$

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3 years ago

Substitute natural gas (SNG) is a gaseous mixture containing CH4(g) that can be used as a fuel. One reaction for the production

Lynna [10]

Answer:

ΔH° of the reaction is -747.54kJ

Explanation:

Based on gas law, it is possible to find the ΔH of a reaction using ΔH of half reactions.

Using the reactions:

(1) C(graphite) + 1/2O₂(g) → CO(g) ΔH° = -110.5 kJ

(2) CO(g) + 1/2O₂(g) → CO₂(g) ΔH° = -283.0 kJ

(3) H₂(g) + 1/2O₂(g) → H₂O(l) ΔH° = -285.8 kJ

(4) C(graphite) + 2H₂(g) → CH₄(g) ΔH° = -74.81 kJ

(5) CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) ΔH° = -890.3 kJ

The sum of 4×(4) + (5) gives:

4C(graphite) + 8H₂(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -74.81 kJ ×4 - 890.3 kJ = -1189.54kJ

Now, this reaction - 4×(1) gives:

4CO(g) + 8H₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -1189.54kJ - 4×-110.5 = -747.54kJ

Thus ΔH° of the reaction is -747.54kJ

3 0

3 years ago