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IgorLugansk [536]
3 years ago
12

¿ Cual es la concentración de 250 ml de una solución que se preparo con 30 gramos de NaOH y agua?

Chemistry
1 answer:
Marysya12 [62]3 years ago
6 0

Answer:

3400

Explanation:

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The kinetic energy is increasing, and the potential energy is decreasing.

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7 0
3 years ago
What amount of moles of sodium chloride is needed to prepare 1.25 L of a salt solution with a concentration of 0.750 mol/L
stellarik [79]

Answer:

Number of moles = 0.94 mol

Explanation:

Given data:

Number of moles of sodium chloride = ?

Volume of sodium chloride = 1.25 L

Concentration of solution = 0.750 mol/L

Solution:

Formula:

Concentration = number of moles/ volume in L

By putting values.

0.750 mol/L = number of mole / 1.25 L

Number of moles =  0.750 mol/L×1.25 L

Number of moles = 0.94 mol

4 0
3 years ago
Calculate the pH of mixing 24 mL of 1M acetic acid with 76 mL of 1M sodium acetate. For the purpose of this calculation, assume
FromTheMoon [43]

Answer:

pH = 5.24

Explanation:

Mixture of acetic acid with acetate ion is a buffer (Mixture of a weak acid with its conjugate base). The pH of a buffer can be determined using Henderson-Hasselbalch equation:

pH = pKa + log₁₀ [A⁻] / [HA]

<em>Where pKa is -log Ka = 4.74; [A⁻] is the concentration of conjugate base (Acetate ion) and [HA] is molar concentration of the weak acid.</em>

Concentration of the acetic acid in the 100mL≡0.1L (76mL + 24mL) solution is:

[HA] = 0.024L ₓ (1mol / L) / 0.1L = 0.24M

[A⁻] = 0.076L ₓ (1mol / L) / 0.1L = 0.76M

Replacing in H-H equation:

pH = 4.74 + log₁₀ [0.76M] / [0.24M]

<h3>pH = 5.24</h3>

<em />

7 0
4 years ago
Please answer this for me, by saying a,b,c, or d
liubo4ka [24]
I think it is D
It’s D I think
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2 years ago
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