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Law Incorporation [45]
2 years ago
15

A 5 g sample of pure gold has a density of 19.3 g/ml. Your friend purchased a gold ring that was made of 25 g of pure gold. What

is the density of the ring?
Chemistry
2 answers:
Butoxors [25]2 years ago
8 0

Answer:

96.5 g/ml

Explanation:

patriot [66]2 years ago
7 0

Answer:

96.5 g/ml

Explanation:

If 5g is 19.3 then 25g is 19.3x5 which is 96.5 g/ml

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( BRAINLIEST) Which of these statements best describes an Alkali? *
Bad White [126]

Answer:

soluble base

Explanation:

as alkali is a salt used as base

7 0
3 years ago
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Metals are considered to be ___________________ because they let electricity flow.
Yuri [45]

Answer:

conductors

Explanation:

Because they consist of lattice of atoms with free electrons and these free electrons allows current to flow through.

5 0
3 years ago
Your dad is working on creating a brick border for the lake in your backyard each brick has a mass of 100 g and a volume of 20 c
wel

Answer:

5000kg/m³

Explanation:

density=mass/volume

d=m/v

d=100/20

=5g/cm³

g/cm³*1000=kg/m³

5g/m³*1000=5000kg/m³

4 0
2 years ago
Read 2 more answers
____________ properties include melting point, boiling point, strength, and malleability.a.physicalc.chemicalb.reactived.none of
lina2011 [118]
Physical properties are those which can be observed without any change in composition of the substance. Hence, a is the answer.
8 0
3 years ago
I'm stuck on this assignment, +20 PTS and BRAINLIEST for step by step:
dolphi86 [110]

Answer:

2. 2.74 L

3. 488 K

4. 7.47 L

5. 38.6 L

6. 2.85 mol

7. 319 K

8. 3.43 kPa

Explanation:

Generally speaking, you want to convert units to SI units, but in this case, we are working with ratios.  This makes up for using the units that wouldn't appropriate elsewhere.

2.  Use the equation P₁V₁ = P₂V₂.  Solve for V₂.  

(3.05 L)(870 kPa) = (969 kPa)(V₂)  

V₂ = 2.74 L.  

3.  Use the equation V₁/T₁ = V₂/T₂. Solve for T₂.  

(3.32 L)/(360 K) = (4.50 L)/(T₂)  

T₂ = 488 K.

4.  Do the same as above, but for V₂.  

(5.10 L)/(-56°C) = V₂/(-82°C)  

V₂ = 7.47 L

5.  Use the equation V₁/n₁ = V₂/n₂.  Solve for V₂.  

(37.2 L)/(0.750 mol) = (V₂)/(0.778 mol)  

V₂ = 38.6 L

6.  Do the same as above, but for n₂.

(86.0 L)/(2.65 mol) = (92.5 L)(n₂)  

n₂ = 2.85 mol

7.  Use the equation P₁/T₁ = P₂/T₂.  Solve for T₂.  

(3.00 atm)/(390 K) = (2.45 atm)/(T₂)  

T₂ = 319 K

8.  Do the same as above, but for P₂.  

In this specific case, however you will need to convert units.  Since both temperatures don't have the same sign, the ratio won't come out right.  Convert to Kelvin.  Add 273.15 to the temperature in Celsius to convert to Kelvin -12.3°C = 260.85 K  25°C = 298.15 K.

(3.00 kPa)/(260.85 K) = P₂/(298.15 K)

P₂ = 3.43 kPa

There is a lot in here... If you are confused about something, let me know!

6 0
3 years ago
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