Solve for X : 2 ≥ x3=6 i will give brainliest

Please help!!!!!!!!!! !!

mestny [16]

Answer:

$The ~length~ is ~9.6~ units$ ✔︎

༄❁༄❁༄❁༄❁༄

$a=8\\b=2\\c=?\\d=?\\e=5$

$Using~ Pythagorean ~theorem:$

$c^2=a^2+b^2$

$c^2=(8)^2+(2)^2$

$\sqrt{c^2} =\sqrt{68}$

$c=\sqrt{68} ~or~2\sqrt{17}$

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$d^2=c^2+e^2$

$d^2=(2\sqrt{17})^2+(5)^2$

$d^2=68+25$

$\sqrt{d^2} =\sqrt{93}$

$d=\sqrt{93} ~or~9.6$

$So, your~ answer ~is ~9.6$

✧⋄⋆⋅⋆⋄✧⋄⋆⋅⋆⋄✧⋄⋆⋅⋆⋄✧⋄⋆⋅⋆⋄✧

hope it helps...

have a great day!!

3 0

3 years ago

Read 2 more answers

You have 10 gallons of lemonade to sell. (1 gal $\approx$ 3785 cm3) a. Each customer uses 1 paper cup. The cups are sold in pack

SpyIntel [72]

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

Calculating the volume of cone cup:

$= \frac{1}{3}\pi r^2 h \\\\ = \frac{1}{3}\times 3.14 \times 4^2 \times 11 \\\\ = \frac{1}{3}\times 3.14 \times 16 \times 11 \\\\ = \frac{1}{3}\times 3.14 \times 176 \\\\ = 3.14 \times 58.66 \cong 184.31 cm^3$

$\to 10 \ gal \times 3,785\ \frac{cm^3}{gal} = 37,850\ cm^3\\\\\to 37,850 cm^3 \times \frac{(1 \ cone)}{(184.31 \ cm^3)} \times 205.4 \ cones$

When buying 5 packages (250 cones):

$\to 8 \ gal \times 3,785 \ \frac{cm^3}{gal} = 30,280\ cm^3 \\\\\to 30,280 \ cm^3 \times \frac{(1\ cone)}{(184.31 \ cm^3)} \cong \ 165 \ cones$

Calculating the left over cones values:

$\to 250 - 165 = 85$

8 0

2 years ago

What's up, my mammals? This is Sid the sloth from the movie "Ice Age". And we're about to do this new dance, the "Continental Dr

Bogdan [553]

Answer:

this question > any other question

Step-by-step explanation:

4 0

3 years ago

Add. −38+(−2910) Enter your answer as a simplified fraction by filling in the boxes.

Pavel [41]

Answer:

-2948

Step-by-step explanation:

Two signs (addition and subtraction) together makes subtraction when having a positive sign and a negative sign

Then subtract -38 and 2910

6 0

2 years ago

If the perimeter of a right triangle is 42 units and the length of the hypotenuse is 20 units, find the length of the other two

Mashutka [201]

So
a^2+b^2=c^2
c=hypotenuse
a^2+b^2=20^2=400

if the permiter is 42 then
p=hypotonuse+side+side
42=20+side+side
subtract 20 from both sides
22=side+side

a+b=22
subtract b from both sides
a=22-b
subsitute for a in equation below
a+2+b^2=c^2
(22-b)^2+b^2=400
b^2-44x+484+b^2=400
2b^2-44x+484=400
divide both sides by 2
b^2-22x+242=200
subtract 200 from both sides
b^2-22x+42=0
factor
(b+/-number)(b+/-number)
to find the numbers, find which 2 number multiply to 42 and add to get -22
the numbers must be neative since same signs multiplied=positive and negative+negative=negative
(b-number)(b-number)
facrors of 42=2,3,6,7,14,21
2,21
3,14
6,7
it's hard to find the number, but the numbers are -19.8882 and -2.11181
(b-19.8882)(b-2.11181)=0
if xy=0 then assume that x and y=0

b-19.8882=0
add 19.8882 to both sides
b=19.8882

b-2.11181=0
add 2.11181 to both sides
b=2.11181

the side legnths are 19.8882 units and 2.11181 units

4 0

3 years ago