Question

a football was kicked vertically upward from a height of 4 feet with an initial speed of 65 feet per second. the formula h=4+65t-16t^2 describes the balls height above ground, h, in feet, t seconds after it was kicked. Use the formula to find the ball's height 2 seconds after it was kicked.

Answer 1

Answer:

70 feet

Step-by-step explanation:

Given

$h=4+65t-16t^2$

Required

Determine h when t = 2

Substitute 2 for t in the given equation

$h=4+65 * 2-16* 2^2$

Solve all exponents

$h=4+65 * 2-16* 4$

$h=4+130-64$

$h=70$