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2 years ago

3 (x-k)/w = 4 solve for x

1 answer:

3 0

Actually the above equation can be solved by following the below steps to fins the value of x Step1: 3(x-k)/w=4 Step 2: (3x-3k)/w=4 Step 3: (3x-3k)=4w Step 4: 3x=4w+3k So hence therefore by following the above steps we can conclude that the value of x is Step 5: x=(4w+3k)/3

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Rewrite in simplest terms:

tangare [24]

Answer:

If one −5s−7(8s−1): -61s+7

If two −5s−7(8s−1): -112s+14

Step-by-step explanation:

-5s-7(8s-1)

Multiply -7 onto 8s and -1:

-5s-56s+7

add -5s and -56s:

-61s+7

−5s−7(8s−1)−5s−7(8s−1)

Multiply both -7 to 8s and -1

-5s-56s+7-5s-56s+7

add:

-112s+14

6 0

2 years ago

Find the equation of the line in slope-intercept form. Slope is −7 and through (−3, 16)

timama [110]

1) Create was we already know in the equation. 16=-7(-3)+b. (This is using the initial equation of y=mx+b.)

2) Simplify and solve for b: 16=21+b = -5=b

3) Replug your be value into your equation: y=-7x-5.

Answer

y=-7x-5

Words: y equals negative seven x, minus five.

6 0

2 years ago

Read 2 more answers

Subtract. (2p^2+q)-(p^2+q) Is the answer P^2 P^2+2q P^2-2q 3p^2

Fofino [41]

Answer:

-p5q2 - p3q5 + 2p3 + 2pq2 + 2q3

____________________________

p3q2

Step-by-step explanation:

Simplify ——

Equation at the end of step 1 :

(p+q) 2

(((2•—————)-(q3))+——)-p2

(p3) q2

Step 2 :

p + q

Simplify —————

p3 (p + q) 2

(((2 • ———————) - q3) + ——) - p2

p3 q2

Step 3 : 2 • (p + q) 2

((——————————— - q3) + ——) - p2

p3 q2 q3 q3 • p3

q3 = —— = ———————

1 p3

4 0

2 years ago

Select the fraction equivalent to 0.1¯

Readme [11.4K]

Answer:

its 1/10

Step-by-step explanation:

You are wrong because 0.1 x 10 is 1 just like 1/10 x 10 is 1.

8 0

2 years ago

I don’t understand this help please

Elodia [21]

Answer:

Step-by-step explanation:

The first simplification we can make is to replace 6^0 with 1.

The first rules of exponents we can apply are ...

(a·b)^c = a^c·b^c . . . . . . similar to the distributive property

 (a^b)^c = a^(b·c)

This reduces your expression to ...

$(2^8\cdot 3^{-5})^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot 2^{28}=2^{8(-2)}\cdot 3^{-5(-2)}\cdot\dfrac{3^{-2(4)}}{2^{3(4)}}\cdot 2^{28}\\\\=2^{-16}\cdot 3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot 2^{28}$

Now we can apply another two rules of exponents:

 (a^b)(a^c) = a^(b+c)

 1/a^b = a^-b

Using these, we have ...

$=2^{-16-12+28}\cdot 3^{10-8}\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9$

The value of the expression is 9.

3 0

3 years ago