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3 years ago

If an object has a density greater than the liquid in which it is placed, I predict that it will:

Physics

1 answer:

inessss [21]3 years ago

4 0

If an object has a density greater than the liquid in which it is placed it will sink.

Explanation:

Density of the object can be known by its mass and volume.

If two objects have same volume but different masses it means the one having more mass will have higher density. Density is amount of mass per unit volume.

Objects that are tightly packed have higher density.

According to Archimedes' principle when a body is fully immersed that an upward buoyant force is equal to weight of the fluid that object displaces.

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10 points!! If you help!!!

marta [7]

For Mass

K.E = (1/2*mv^2)

Explanation:

Kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

4 0

3 years ago

Block A has a mass of 0.5kg, and block B has a mass of 2kg. Block is is released at a height of 0.75 meters above B. The coeffic

VikaD [51]

Answer:

0.075 m

Explanation:

The picture of the problem is missing: find it in attachment.

At first, block A is released at a distance of

h = 0.75 m

above block B. According to the law of conservation of energy, its initial potential energy is converted into kinetic energy, so we can write:

$m_Agh=\frac{1}{2}m_Av_A^2$

where

$g=9.8 m/s^2$ is the acceleration due to gravity

$m_A=0.5 kg$ is the mass of the block

$v_A$ is the speed of the block A just before touching block B

Solving for the speed,

$v_A=\sqrt{2gh}=\sqrt{2(9.8)(0.75)}=3.83 m/s$

Then, block A collides with block B. The coefficient of restitution in the collision is given by:

$e=\frac{v'_B-v'_A}{v_A-v_B}$

where:

e = 0.7 is the coefficient of restitution in this case

$v_B'$ is the final velocity of block B

$v_A'$ is the final velocity of block A

$v_A=3.83 m/s$

$v_B=0$ is the initial velocity of block B

Solving,

$v_B'-v_A'=e(v_A-v_B)=0.7(3.83)=2.68 m/s$

Re-arranging it,

$v_A'=v_B'-2.68$ (1)

Also, the total momentum must be conserved, so we can write:

$m_A v_A + m_B v_B = m_A v'_A + m_B v'_B$

where

$m_B=2 kg$

And substituting (1) and all the other values,

$m_A v_A = m_A (v_B'-2.68) + m_B v_B'\\v_B' = \frac{m_A v_A +2.68 m_A}{m_A + m_B}=1.30 m/s$

This is the velocity of block B after the collision. Then, its kinetic energy is converted into elastic potential energy of the spring when it comes to rest, according to

$\frac{1}{2}m_B v_B'^2 = \frac{1}{2}kx^2$

where

k = 600 N/m is the spring constant

x is the compression of the spring

And solving for x,

$x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(2)(1.30)^2}{600}}=0.075 m$

5 0

3 years ago

A boy 11.0 m above the ground in a tree throws a ball for his dog, who is standing right below the tree and starts running the i

ryzh [129]

12414253

Explanation:

8 0

2 years ago

This is physical education .,.

Paul [167]

Increase the frequency, intensity would increase muscle mass and the other two wouldn't help improve anything

6 0

3 years ago

Read 2 more answers

A proton and an electron are both accelerated to the same final speed. If λp s the de Broglie wavelength of the proton and e is

meriva

Answer:

Explanation:

The relation between the de Broglie wavelength and the momentum of the particle is given by

$\lambda =\frac{h}{m\times v}$

where, m is the mas of the particle and v be the velocity of the particle and h be the Plank's constant.

So, the de broglie wavelength of proton is given by

$\lambda _{p}=\frac{h}{m_{p}\times v}$ .... (1)

The de broglie wavelength of electron is given by

$\lambda _{e}=\frac{h}{m_{e}\times v}$ .... (2)

Divide equation (2) by equation (1), we get

$\frac{\lambda _{e}}{\lambda _{p}}=\frac{m_{p}}{m_{e}}$

As the mass of proton is much more than the mass of electron, so the de broglie wavelength of electron is more than the de Broglie wavelength of proton.

5 0

4 years ago