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Inessa05 [86]
3 years ago
15

22. A race car accelerates from 0.0 m/s to 5 m/s with a displacement of 2.5 m. What is the

Physics
1 answer:
yanalaym [24]3 years ago
6 0

Answer:

Option A

5 m/s^{2}

Explanation:

From fundamental equation of motion

v^{2}=u^{2}+2as where v is the final velocity, u is the initial velocity, a is the acceleration of the body and s is the displacement.

Since the initial velocity is zero

v^{2}=2as

Making acceleration, a the subject of the formula then

a=\frac {v^{2}}{2s}

Substituting 5 m/s for v and 2.5 m for s then

a=\frac {5^{2}}{2\times 2.5}=5 m/s^{2}

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Answer:

a)  x(t) = 10t + (2/3)*t^3

b) x*(0.1875) = 10.18 m

Explanation:

Note: The position of the horse is x = 2m. There is a typing error in the question. Otherwise, The solution to cubic equation holds a negative value of time t.

Given:

- v(t) = 10 + 2*t^2 (radar gun)

- x*(t) = 10 + 5t^2 + 3t^3  (our coordinate)

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-The position x of horse as a function of time t in radar system.

-The position of the horse at x = 2m in our coordinate system

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- The position of horse according to radar gun:

                              v(t) = dx / dt = 10 + 2*t^2

- Separate variables:

                              dx = (10 + 2*t^2).dt

- Integrate over interval x = 0 @ t= 0

                             x(t) = 10t + (2/3)*t^3

- time @ x = 2 :

                              2 = 10t + (2/3)*t^3

                              0 = 10t + (2/3)*t^3 + 2

- solve for t:

                              t = 0.1875 s

- Evaluate x* at t = 0.1875 s

                              x*(0.1875) = 10 + 5(0.1875)^2 + 3(0.1875)^3

                              x*(0.1875) = 10.18 m

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