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Talja [164]
3 years ago
12

under normal conditions describe how increasing the temperature affects the solubility of a typical salt

Physics
1 answer:
Eduardwww [97]3 years ago
8 0
For many solids dissolved in liquid water, the solubility increases with temperature. The increase in kinetic energy that comes with higher temperatures allows the solvent molecules to more effectively break apart the solute molecules that are held together by intermolecular attractions.
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He formula p=m x v to answer th<br>2,000 kg car moving at 30 m/s​
aivan3 [116]

The momentum of the car is 60,000 kg m/s

Explanation:

The momentum of an object is a vector quantity, whose magnitude is given by

p=mv

where

m is the mass of the object

v is its velocity

For the car in this problem, we have

m = 2,000 kg

v = 30 m/s

Therefore, the magnitude of its momentum is

p=(2000)(30)=60,000 kg m/s

Learn more about momentum here:

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#LearnwithBrainly

7 0
3 years ago
A 14-foot boat operating under oars after dark must show what color light to prevent a collision?
Tomtit [17]
<span>A "White" colored light must be shown by a 14-foot boat that is operating under oars after it is dark, in order to prevent a collision.

Boats which are less than 23 feet cannot exceed a maximum speed of 7 knots. They need to exhibit an all-around white light when it is sailing in the dark.

The other practicable sidelights can also be used instead of the white lights, when they are sailing in international waters.
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7 0
3 years ago
What do we mean by principle of conservation?​
leonid [27]

Answer:

Conservation principles tell us that some<u> quantity, quality, or aspect remains constant through change. </u>

Explanation:

7 0
3 years ago
PLEASE HELP!!<br><br> i’ll mark brainliest if you’re correct
Leno4ka [110]
5Newtons or 5N

Ten newtons minus five Newton’s is 5 Newton’s
5 0
2 years ago
Read 2 more answers
An object is dropped from an altitude of one Earth radiusabove Earth's surface. If M is the mass of Earth and R is itsradius the
Montano1993 [528]

Answer:

The speed of the object just before it hits Earth is  \sqrt{\dfrac{GM}{R}}

(A) is correct option.

Explanation:

Given that,

M = mass of earth

R = radius of earth

The potential energy at height above the surface of the earth

P.E=-\dfrac{GmM}{R+h}

The kinetic energy at height above the surface of the earth

K.E = 0

The total energy at height above the surface of the earth

E = K.E+P.E

E = -\dfrac{GmM}{R+h}....(I)

The total energy at the surface of the earth

E'=\dfrac{1}{2}mv^2-\dfrac{GmM}{R}....(II)

We need to calculate the speed of the object  just before it hits Earth

From equation (I) and (II)

-\dfrac{GmM}{R+h}=\dfrac{1}{2}mv^2-\dfrac{GmM}{R}

Here, h = R

-\dfrac{GmM}{2R}=\dfrac{1}{2}mv^2-\dfrac{GmM}{R}

v= \sqrt{\dfrac{GM}{R}}

Hence, The speed of the object just before it hits Earth is  \sqrt{\dfrac{GM}{R}}.

4 0
3 years ago
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