Answer: 0.2 hours
Explanation: In order to solve this question we have to considerer that a recargeable battery can supply 1800 mA in one hour then we have to determine how long could this battery drive current through a long, thin wire of resistance 34 Ω .
Besides, this battery has a voltage of 12 V
so by using the Ohm law we also know that V=R*I,
Fron this we can obtain:
I= V/R= 12 V/ 34 Ω=0.35 A= 350 mA
then considering that this battery can supply 1800 mA in one hour we have this battery can supply 350 mA in x time in the form:
1hour------- 1800 mA
x hour--------350 mA
time= 350/1800= 0.2 hour
Answer:
microscopic means that they are very very tiny, you cannot see them with the human eye, you have to use a tool like a microscope
Explanation:
Answer:
yes
it does you weigh less on the equator than at the North or South Pole, but the difference is small. Note that your body itself does not change. Rather it is the force of gravity and other forces that change as you approach the poles. These forces change right back when you return to your original latitude.
Answer:
Which sentence from the passage shows that the function of the river depicted here has carried through to modern times?
Explanation:Which
sentence from the passage shows that the function of the river depicted here has carried through to modern times?
Answer:
θ '= 4975 rev
Explanation:
For this exercise let's use the relationship between work and the change in kinetic energy
W = ΔK
the expression for work is
W = - τ Δθ
where the negative sign indicates that the torque is in the opposite direction to rotation
kinetic energy
K = ½ I w²
we substitute
- τ Δθ = 0 - ½ I w²
θ = 
if we approach the rotor to a cylinder with an axis of rotation through its center
I = ½ m r²
we substitute
θ = ½ (½ m r²) 
How the measurements are in the English system, the weight
W = m g
m = W / g
let's reduce to the english system
w = 3600 rev / min (2pi rad / 1rev) (1 min / 60s) = 376.99 rad / s
r = 9 in (1 ft / 12in) = 0.75 ft
let's calculate
m = 125/32 = 3.91 slug
θ = ¼ 3.91 0.75² 376.99² / 2.5
θ = 3.126 10⁴ rad
let's reduce to revolutions
θ’= 3.126 10⁴ rad (1rev / 2π rad)
θ’= 4974.9 rev
θ '= 4975 rev
