C/2 - 3 + 6/d when c=14 d=3
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Given:
Seven times the smaller of two consecutive even integers is the same as -300 minus 4 times the larger integer.
To find:
The integers .
Solution:
Let the smaller even integer be x.
So, larger even integer is x+2 because they are consecutive even integers.
Seven times the smaller integer = 7x
-300 minus 4 times the larger integer = -300-4(x+2)
Now,
Divide both sides by 11.
So, the smaller even integer is -28.
So, the larger even integer is -26.