Question

What is the width of todors area model? 10x exponent2 -5x 15

Answer 1

Answer:

The width of the area model is equal to

$(2x^2-x+3)\ units$

Step-by-step explanation:

The complete question is

Todor was trying to factor 10x^2-5x+15 he found the greatest common factor of these terms was 5 what is the width

we know that

The area of a rectangular model is given by the formula

$A=LW$ ----> equation A

where

L is the length

W is the width

we have

$A=10x^2-5x+15$

Factor the expression

$A=5(2x^2-x+3)$

substitute the value of the Area in the equation A

$5(2x^2-x+3)=LW$

In this problem

The greatest common factor of these terms is the length (L=5 units)

so

we can say that the width is equal to (2x^2-x+3)

therefore

The width of the area model is equal to

$(2x^2-x+3)\ units$