PLEASE HELP ME OUT <br> EASY POINTS HERE :)

Organisers want to raise a total of £250 for a new equipment. The sponsored walk raises £150. What % of the total does the spons

Zinaida [17]

150/250 = 0.6 = 60% <==

5 0

3 years ago

Match the key aspect of a function's graph with its meaning

Aliun [14]

Answer:

y- intercept --> Location on graph where input is zero

f(x) < 0 --> Intervals of the domain where the graph is below the x-axis

x- intercept --> Location on graph where output is zero

f(x) > 0 --> Intervals of the domain where the graph is above the x-axis

Step-by-step explanation:

Y-intercept: The y-intercept is equivalent to the point where x= 0. 'x' is the input variable in an equation, therefore the y-intercept is where the input, or x, is equal to 0.

f(x) <0: Notice the 'lesser than' sign. This means that the value of f(x), or 'y', is less than 0. This means that this area consists of intervals of the domain below the x-axis.

X-intercept: The x-intercept is the location of the graph where y= 0, or the output is equal to 0.

f(x) >0: In this, there is a 'greater than' sign. This means that f(x), or 'y', is greater than 0. Therefore, this consists of intervals of the domain above the x-axis.

8 0

2 years ago

Write an equation of the line given.

frozen [14]

Answer:

y = -3/4x + 1

Step-by-step explanation:

6 0

3 years ago

A group of friends were working on a student film that had a budget of $600. They used $198 of their budget on props. What perce

uranmaximum [27]

Pretty sure it is 33% because 198/600 is 33.

3 0

1 year ago

One study reports that 34% of newly hired MBAs are confronted with unethical business practices during their first year of empl

MaRussiya [10]

Answer:

$z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364$

$p_v =2*P(Z$

The p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.

Step-by-step explanation:

1) Data given and notation

n=116 represent the random sample taken

X represent the number graduates from the previous year claim to have encountered unethical business practices in the workplace

$\hat p=0.28$ estimated proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace

$p_o=0.34$ is the value that we want to test

$\alpha=0.05$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is 0.34 or no.:

Null hypothesis: $p=0.34$

Alternative hypothesis: $p \neq 0.34$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(Z$

The p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.

5 0

3 years ago

PLEASE HELP ME OUT EASY POINTS HERE :)