For this, we need to find the area of the larger rectangle (The room) and subtract from that the area of the smaller, shaded rectangle (The rug).
A=LW (L=Length, W=Width, A=Area)
The larger rectangle first:
A=(15)(10)
A=150 feet squared
Now the Rug:
A=(12)(7)
A=84 feet squared
Now to find the area that is NOT covered by the rug, we subtract:
150-84
= 66 feet squared will NOT be covered by the rug.
Hope this Helps!
-Sinnamin
Answer:
Step-by-step explanation:
h^2=x^2+y^2, here x and y are equal so we can say
h^2=2x^2, we see that h=2(2^(1/2)) so
2x^2=8
x^2=4
x=2
Answer:
P( sum is prime )= 73/216
Step-by-step explanation:
The minimum value of the sum will be 3 and maximum value will be 18. So the prime numbers in this range are 3 , 5, 7, 11, 13, 17.
P(sum=3)=1/216, P(sum=5)=6/216, P(sum=7)=15/216, P(sum=11)=27/216, P(sum=13)=21/216, P(sum=17)=3/216.
The final probability will be sum of the above given probabilities.
Hence P( sum is prime )= 73/216
Answer:
x=4 Inch
Step-by-step explanation:
Length of the Square = 24 Inches
If a Square of Length x cm is cut out from each corner
Length of the Box = 24-x-x=(24-2x) Inches
Width of the Box =24-x-x=(24-2x) Inches
Height of the box = x inches
Volume of a Cuboid = Length X Width X Height
V(x)= x(24-2x)(24-2x)
Simplifying
V(x)=4x(12-x)(12-x)
To determine the value of x at which V is largest, we take the derivative of V(x) and solve for the critical points.
V(x)=4x(12-x)(12-x)

Set the derivative equal to zero to obtain the critical points

x cannot be equal to 12 as it divides the length of the square cardboard into exactly two equal parts.
When x=4
V(4)=4*4(12-4)(12-4)=16*8*8=1024 Cubic Inches
When x=4 Inch, the volume, V of the open box is largest.