Answer:
Lucas needs 12 cups of dried cherries and 24 cups of dried apricots to make one dozen of snacks for his team
Step-by-step explanation:
For each snacks Lucas uses one cup of dried cherries and 2 cup of dried apricots. One dozen of snack contains a total of 12 snacks. Therefore to prepare 12 snacks (one dozen) the number of dried cherries and dried apricots can be gotten by multiplying the number of dried cherries and dried apricots required for each snack by 12.
Number of dried cherries = 1 cup for each snack × 12 snacks = 12 cups
Number of dried apricots = 2 cup for each snack × 12 snacks = 24 cups
Lucas needs 12 cups of dried cherries and 24 cups of dried apricots to make one dozen of snacks for his team
Here you go . 146 is the answer with the work shown.
Sir you don’t even have a question
Instead of X put 5 and instead of y put 2
5+6(2)
5+12= 17
1.) Let's say that the circle on the graph below represents x. The arrow is pointing to all the numbers greater than x, which happens to be on -2. If it points right, this means that x can equal to any number greater than -2. So your answer is x > -2.
2.) For inequalities such as these, you can simplify just like what you do for normal equations. Let's isolate x.

--> 
---> 
3.) 
--> 
---> 
4.) 
--> 
---> 
----> 
-----> 
5.) 
--> 
---> 
----> 
-----> 