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Semmy [17]
3 years ago
7

-3(x+2)=16-x How do you solve this problem?

Mathematics
1 answer:
siniylev [52]3 years ago
8 0

Answer:

x=-11

Step-by-step explanation:

-3(x+2)=16-x

start with parenthesizes

-3*x=-3x

-3*2=-6

so you get

-3x-6=16-x

add the 6 to both sides

-3x=22-x

add x

-2x=22

divide by -2

x=-11

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Answer:

actually it's 234

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Step-by-step explanation:

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2 years ago
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A weighted coin has a 0.599 probability of landing on heads. What is the probability that it takes 5 flips for the first head to
natka813 [3]

Answer:

0.411^5 times 0.599

Step-by-step explanation:

0.599 chance of landing on heads.

0.411 chance of not landing on heads.

0.411 times 0.411 times 0.411 times 0.411 times 0.411 (for the 5 flips that do not land on heads) times 0.599 (for the time that it does land on heads).

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A<br><br> B<br><br> C<br><br> Neither of them
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None of them are correct.
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Simplify if x = 5 and y = 4.
Oxana [17]
9 = 20 = 100 = 10 = -8 =
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2 years ago
The sum of the ages of Berma, her mother Rinna and her father Erwin is 80. Two years from now, Rinna’s age will be 13 less than
jekas [21]

Answer: Berma is 5 years old

Rinna is 38 years old

Erwin is 37 years old

Step-by-step explanation:

Let x represent Berma's age

Let y represent Rinna's age

Let z represent Erwin's age

Since the sum of their ages is 80,

x + y + z = 80 - - - - - - -1

Two years from now, Rinna’s age will be 13 less than the sum of Erwin’s age and twice Berma’s age. This means that

y +2 = [ (z+2) + 2(x+2) ] - 13

y +2 = z + 2 + 2x + 4 - 13

2x - y + z = 13 + 2 - 4 -2

2x - y + z = 9 - - - - - - -2

Three years ago, 15 times Berma’s age was 5 less than the age of Rinna. It means that

15(x - 3) = (y - 3) - 5

15x - 45 = y - 3 - 5

15x - y = - 8 + 45

15x - y = 37 - - - - - - - -3

From equation 3, y = 15x - 37

Substituting y = 15x - 37 into equation 1 and equation 2, it becomes

x + 15x - 37 + z = 80

16x + z = 80 + 37 = 117 - - - - - - 4

2x - 15x + 37 + z = 9

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subtracting equation 5 from equation 4,

29x = 145

x = 145/29 = 5

y = 15x - 37

y = 15×5 -37

y = 38

Substituting x= 5 and y = 38 into equation 1, it becomes

5 + 38 + z = 80

z = 80 - 43

z = 37

6 0
3 years ago
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