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mote1985 [20]
2 years ago
9

Sum of 13 and 3 times a number is 31. What is the number?

Mathematics
1 answer:
Volgvan2 years ago
6 0

Answer:

13 + 3x= 31

Step-by-step explanation:

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Find the average. Round your answer to the nearest whole number.<br><br> 8, 12, 7, 5, 2
AVprozaik [17]

Answer:

7

Step-by-step explanation:

8 + 12 + 7 + 5 + 2= 34

34/5 =6.8

Rounded =7

5 0
3 years ago
Please help me I will crown
Naddika [18.5K]

Answer: c

Step-by-step explanation:

3 0
2 years ago
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Simplify<br> Зе –6e + Зе – 4e =<br> How do you do it
Anvisha [2.4K]

Answer:

Let's simplify step-by-step.

3e−6e+3e−4e

=3e+−6e+3e+−4e

Combine Like Terms:

=3e+−6e+3e+−4e

=(3e+−6e+3e+−4e)

=−4e

Step-by-step explanation:

You are welcome

4 0
3 years ago
Investments increase exponentially by
Blizzard [7]

Using an exponential function, it is found that you would have $10,240 after 18 years.

<h3>What is an exponential function?</h3>

An increasing exponential function is modeled by:

A(t) = A(0)(1 + r)^t

In which:

  • A(0) is the initial value.
  • r is the growth rate, as a decimal.

Considering the initial value of $2,500, and the growth rate of 60% every 6 years, the equation is given by:

A(t) = 2500(1.6)^\frac{t}{6}

Hence, after 18 years, the amount is given by:

A(18) = 2500(1.6)^\frac{18}{6} = 10240

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

5 0
2 years ago
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

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6 0
1 year ago
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