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mario62 [17]
4 years ago
14

HURRY PLZ

Mathematics
2 answers:
WITCHER [35]4 years ago
8 0

Answer:

Second option is the correct answer.

Step-by-step explanation:

To know if the given set of numbers can be possible lengths for a right triangle, we will use the Pythagorean theorem that states:

a^{2}+b^{2} =c^{2}

a and b are smaller lengths.

Option first:

6cm, 22.9cm, 20.1cm.

6^{2}+20.1^{2} =22.9^{2}

=> 36+404.01=524.41

=> 440.01\neq 524.41

This is not a right triangle.

Option second:

10.5cm, 20.8cm, 23.3cm

10.5^{2}+20.8^{2} =23.3^{2}

=> 110.25+432.64=542.89

=> 542.89=542.89

This is a right triangle.

AlekseyPX4 years ago
3 0
6^2 + 20.1^2 =? 22.9^2
36 + 404 does NOT equal 524.41
These do NOT form a right triangle.

10.5^2 + 20.8^2 =? 23.3^2
110.25 + 432.64 = 542.89
Therefore, it is a right triangle.


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Micah recorded the amount of time his mom and dad spend reading bedtime stories. He plotted the data in the box plot below.
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Answer:

The lengths of time that his mom reads are typically longer and have more variability than the lengths of time that his dad reads.

Step-by-step explanation:

The Mom's plot is longer in ranges, therefore, she would have more variability than the dad.

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3 years ago
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I think the answer is C is this correct? And if not can I get some help?
blsea [12.9K]

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galben [10]

Answer:

For the first table: (0, 10) (1, 15) (2, 20) (3, 25) (4, 30)

For the second table: (-2, 1.04) (-1, 1.2) (0, 2) (1, 6) (2, 26)

For the third table: (-2, 10) (-1, 0) (-1/2, -5/4) (1, 10)

Step-by-step explanation:

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Answer:

B

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Angle P and Angle Q are co- interior angles so they add up to 180 degrees

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7 0
3 years ago
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
3 years ago
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