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erica [24]
2 years ago
14

thirty tickets were sold for a concert, some at 60 cent and the rest is at $1. If the total was raised to $22, how many had the

cheaper tickets.
Mathematics
1 answer:
katrin [286]2 years ago
3 0

Answer:

20

Step-by-step explanation:

To solve this question we can use a system of linear equations. The 2 equations should represent- 1) the number of total tickets sold and 2) the total amount raised. So, the two equations look like this (in this situation, let x stand for the cheaper tickets and y for the more expensive ones).

  • x+y=30
  • 0.6x+1y=22

Then, there are multiple ways to solve this including graphing, elimination, and substitution. In my opinion, substitution is the best for this situation.

Firstly, isolate the y variable in the first equation

  • y=30-x

Next, plug in this value for y in the second equation

  • 0.6x+(30-x)=22

Then, solve this equation algebraically

  • x=20

Since x stands for the cheaper tickets, we know that 20 people bought the cheaper tickets.

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Step-by-step explanation by elimination:

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