Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
Answer:
The answer is 15
Step-by-step explanation:
I know and is not stupid
Answer:
20
Step-by-step explanation:
If you need the step-by-step explanation please reach out to me!
What can be proven true in the diagram is the statement in letter C. angle CGB is complementary to angle AGD. It is because they both had the same vertex which is point G. Complementary angles are angles which are equal to 90 degrees wherein when you add both angles which are obviously 45 degrees, the sum is 90 degrees.
