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ValentinkaMS [17]
3 years ago
13

What value of x is in the solution set of 2(3x – 1) > 4x – 6?

Mathematics
2 answers:
ANTONII [103]3 years ago
7 0

Answer: x > -2

Step-by-step explanation:

2(3x−1)>4x−6

Step 1: Simplify both sides of the inequality.

6x−2>4x−6

Step 2: Subtract 4x from both sides.

6x−2−4x>4x−6−4x

2x−2>−6

Step 3: Add 2 to both sides.

2x−2+2>−6+2

2x>−4

Step 4: Divide both sides by 2.

2x/2>−4/2

x>−2

Semmy [17]3 years ago
3 0

Answer:

The answer to your question is    (-2, ∞)      

Step-by-step explanation:

Data

                 2(3x - 1) > 4x - 6

Process

-Expand

                6x - 2 > 4x - 6

-Subtract 4x in both sides

                6x - 4x - 2 > 4x - 6 - 4x

-Simplify

                 2x -2 > -6

-Add 2 in both sides

                 2x - 2 + 2 > -6 + 2

-Simplify

                 2x > -4

-Divide by 2 both sides

                 2x/2 > -4/2

-Simplify

                   x > -2

-Result

All the numbers higher than -2

                   (-2, ∞)      

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h x 10 + p x .25 = maggies earnings

Part A
h x 10 + 60 x .25 = 115

Part B
h x 10 + 15 = 115 (multiplied 60 x .25)
h x10 = 100 (subtracted 15 from each side of the equation)
h = 10 (divided 10 into each side)

Part C
10 hrs

Hope this helps

3 0
2 years ago
Read 2 more answers
Is it ok you guys maybe do this one too sorry...<br> (−6)(−0.4)(−0.5)
olchik [2.2K]
(-6)(-0.4)(-0.5) = (-1)6⋅4⋅5⋅10⁻² = -1.2
5 0
3 years ago
Z divided by 3-2z + 4(z-8) when z = 18 <br><br> A. -122<br> B. 6<br> C. -66<br> D. 10
murzikaleks [220]

Everywhere you see z, replace the letter with 18.

z/[(3- 2z)] + 4(z - 8)

18/[(3 - 2(18))] + 4(18 - 8)

You finish.

3 0
2 years ago
How do I solve this?
iren2701 [21]

Answer:

Firstly find the area of the square and then the area of the two triangles and then plus it. That's what I think I tried

5 0
3 years ago
How do I solve this?
iris [78.8K]

Answer:

Step-by-step explanation:

From the picture attached,

Addition of the blocks in first row is 60

a + a + a + 12 = 60

3a + 12 = 60

3a = 60 - 12

3a = 48

a = 16

For second row,

(b + 5) + (b + 5) + (b + 5) + (b + 5) = 60

4(b + 5) = 60

b + 5 = 15

b = 10

For third row,

(a + b) + c = (b + 5) + (b + 5) + (b + 5)

a + b + c = 3(b + 5)

16 + 10 + c = 3(10 + 5) [Since, a = 16 and b = 10}

26 + c = 45

c = 45 - 26

c = 19

For fourth row,

3c + d = 60

3(19) + d = 60

57 + d = 60

d = 60 - 57

d = 3

8 0
2 years ago
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