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Luba_88 [7]
3 years ago
15

Are all real numbers, rational numbers?

Mathematics
1 answer:
Alex777 [14]3 years ago
6 0
Hi there!

FALSE !!
" Are all real numbers are rational numbers "

\bf{EXPLANATION} :-

Real number is a set of all the numbers.
Each and every kind of number, rational or irrational will be considered as a real number

Every rational number is real. But, Not all real numbers are rational.

~ Hope it helps!
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Here are the test scores for 10 students in Mr. P's class.
lutik1710 [3]
  • We need mean

\\ \rm\hookrightarrow Mean=\dfrac{Sum}{n}

\\ \rm\hookrightarrow \dfrac{59+94+57+87+75+90+82+57+65+77}{10}

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7 0
3 years ago
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
Given the polynomial 21x 4 + 3y - 6x 2 + 34 What polynomial must be subtracted from it to obtain 29x 2 - 7 ? What polynomial mus
fredd [130]

Answer:

1. 21x⁴+3y-35x² + 41

2. -21x⁴-3y+6x² + x

Step-by-step explanation:

When adding and subtracting polynomials , you can use the distributive property to add or subtract the coefficients of like terms.

1. The polynomial is 21x⁴ + 3y -6x² + 34

To obtain polynomial 29x² -7 , we must subtract some polynomial from it.

Let that polynomial be k.

So, 21x⁴ + 3y -6x² + 34 - k =  29x² -7

k = 21x⁴ + 3y - 6x² +34 - 29x² +7 = 21x⁴ + 3y - 35x² + 41

2. To obtain a first degree polynomial, let that polynomial be x +34

So, 21x⁴ + 3y - 6x² + 34 + K = x + 34

K = x + 34 - 21x⁴ -3y + 6x² - 34

  = -21x⁴ - 3y + 6x² + x

6 0
3 years ago
Jackson's hair was 7 centimeters long after his last haircut, and it grows 5 centimeters every year. Jackson last got his hair c
ahrayia [7]
37 cm sijsuensneneuxkeme
7 0
3 years ago
I need help with these 2 problems. Please and thank you :)
dsp73

Answer:

2,8

Step-by-step explanation:

the upper arrow goes down just like the other one so which every number you see its on go to that number and look up im at explaining but that is the answer for the 1st page

7 0
2 years ago
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