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3 years ago

Solve for the roots in simplest form using the quadratic formula: x^2 + 61 =-10x

Mathematics

1 answer:

Yakvenalex [24]3 years ago

6 0

9514 1404 393

Answer:

-5 ± 6i

Step-by-step explanation:

To use the quadratic formula, we need the equation in standard form. Adding 10x gives ...

x^2 +10x +61 = 0

Then a=1, b=10, c=61, and the solutions are ...

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4(1)(61)}}{2(1)}\\\\=\dfrac{-10\pm\sqrt{-144}}{2}=\dfrac{-10\pm12i}{2}\\\\ \boxed{x=\{-5-6i,-6+6i\}}$

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Answer:

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Step-by-step explanation:

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3 years ago

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In ΔJKL, the measure of ∠L=90°, JL = 80, KJ = 89, and LK = 39. What is the value of the sine of ∠J to the nearest hundredth

emmainna [20.7K]

Given:

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To find:

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