Answer:
the geometric series is a(n) = -12(3)^(n-1)
Step-by-step explanation:
"Triple" denotes multiplication by 3. Thus, the common factor here is 3.
The general formula for a geometric series is a(n) = a(1)(r)^(n-1), where a(1) is the first term, r is the common ratio.
Here, we have a(n)= (-12)(3)^(n-1) = -972.
We need to solve this for n, which represents the last term.
The first step towards solving for n is to divide both sides by -12:
3^(n-1) = 81
To solve for n-1, rewrite 81 as 3^4. Then we have:
3^(n-1) = 3^4, implying that (n-1) = 4 and that n = 5.
Then we know that it is the 5th term that equals -972.
In summary, the geometric series is a(n) = -12(3)^(n-1).
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