Solve the system by substitution.<br> y=2x<br> -3x + 8y =26

What is g(x) I need your help

velikii [3]

Answer:

D , i thinks this is the answer because i cant see the g(x) good

Step-by-step explanation:

5 0

2 years ago

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

2 years ago

Help PLZ HAVENT HAD HELP IN TWO HOUR JUST ONE QUESTION One card is to be drawn from a deck of 52 cards.The deck includes four ty

Vitek1552 [10]

Answer:

FOR red one = 1/26

FOR black three = 1/26

FOR six of hearts = 1/52

Step-by-step explanation:

TECHNICALLY EVERY CARD WOULD BE 1/52 BUT SINCE THERE R TWO DIFFERENT TYPES OF BLACKS AND REDS THE FIRST TWO ARE 1/26

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

PEACE!

7 0

2 years ago

Write the English phrase as an algebraic expression. Then simplify the expression. Let x represent the number.

Trava [24]

Answer:

Step-by-step explanation:

6 0

2 years ago

Select the graph for the solution of the open sentence. Click until the correct graph appears. |x| > 4

nadezda [96]

Answer:

***********o o**************

<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->

x>4 or x<-4

Step-by-step explanation:

You are looking for numbers that give you a distance, x, greater than 4 from 0. That wouldn't be anything between -4 and 4 because these would all give you a distance less than 4 from 0. So the answer would be to shade everything greater than 4 while also shading everything less than -4.

Here is a number line <-----|-----|-----|-----|-----|-----|-----|-----|-->

-6 -4 -2 0 2 4 6 8

Let's think about this more which of these numbers on this number line would satisfy |x|>4?

Numbers inside the numbers -4 and 4.

Or the numbers on the outside.

Let's try the inside numbers:

-2,02

|-2|>4

2>4 is false which means -2 doesn't satisfy |x|>4

|0|>4

0>4 is false which means 0 doesn't satisfy |x|>4

|2|>4

2>4 is false which means 2 doesn't satisfy |x|>4

We could also try -4 and 4... but these will both give you a distance equal to 4 from 0. And we are looking for greater than.

|-4|>4

4>4 is false which mean -4 doesn't satisfy |x|>4

|4|>4

4>4 is false which means 4 doesn't satisfy |x|>4

Now let's try the numbers on the outside:

-6,6,8

|-6|>4

6>4 is true so -6 does satisfy |x|>4

|6|>4

6>4 is true so 6 does satisfy |x|>4

|8|>4

8>4 is true so 8 does satisfy |x|>4

So what I'm trying to do is convince you more that the only numbers that would satisfy |x|>4 are numbers outside the interval from -4 to 4.

So x>4 or x<-4.

On a number line the solution would look like this:

***********o o**************

<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->

We have holes at -4 and 4 to mean we do not include those numbers. We would have if the inequality read $|x| \ge 4$ . The line underneath this inequality means to include or equals. We do not want to include; we did not have the equal sign. The only difference between the two solutions would be to fill the holes if you $|x| \ge 4$ .

4 0

2 years ago

Solve the system by substitution. y=2x -3x + 8y =26