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3 years ago

Write 4^0 * 2^2 * 3^3 as a single number BRAINLIEST!!

Mathematics

2 answers:

valkas [14]3 years ago

5 0

Answer:

Step-by-step explanation:

$4^0=1\\2^2=2\cdot2=4\\3^3=3\cdot3\cdot3=27\\\\4^0\cdot2^2\cdot3^3=1\cdot4\cdot27=108$

Ahat [919]3 years ago

3 0

Answer:

108

Step-by-step explanation:

4 to the power of 0 is always 1. multiply to 2 to the power of 2 gives you 4. multiplying 4 to 3 to the power of 3 gives you 108 because 3^3 is 27 but if you multiply that by 4, you get 108

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Replace x with the possible answers and solve to see which ones make the equation true:

5(3) = 15 + 4 = 19. 19 is < 29 so 3 works.

5(4) = 20 + 4 = 24. 24 is < 29, so 4 also works.

5(5) = 25 + 4 = 29. 29 is not less than 29 so doesn't work.

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Please help me solve question 2

sergiy2304 [10]

Answer:

solution: ( 3 , 6 )

$\sf y =6$

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Step-by-step explanation:

$\sf y = \frac{2}{3} x+4$

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make y the subject in equation 2:

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insert this in equation 1:

$\sf \frac{24-2x}{3} =\frac{2}{3} x+4$

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solve for y:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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