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Hitman42 [59]
3 years ago
14

The following numerically ordered sequence of numbers has a mean of 17 and a median of 18.

Mathematics
1 answer:
Arisa [49]3 years ago
8 0

a= 9

b= 19

hope this helps

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How to write out 314,207
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Three hundred fourteen thousand, two hundred seven. hope this helps
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Which expression will you generate if you combine the like terms in 5x + 6x + y + y + 3y + 4 + 6 + 2?
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Answer:

5x and 6x both have the letter x. Let's combine them! 5x+6x = 11x

y, y, and 3y all have the letter y. You can imagine y to be 1y, they're the same.

1y + 1y + 3y = 5y

4, 6, and 2 don't have any letters. 4 + 6 + 2 = 12

Now you have to put all the final terms together to get: 11x + 5y +12

Step-by-step explanation:

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Which best explains why the equation y=2x+3 does or does not represent a proportional relationship?
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It represents a non-proportional relationship

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Verify cot x sec^4x=cotx +2tanx +tan^3x
Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

Verifying from left, we have

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { \tan}^{2} x )^{2}

Expand the perfect square in the right:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { 2\tan}^{2} x  + { \tan}^{4} x)

We expand to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  \cot(x){ 2\tan}^{2} x  +\cot(x) { \tan}^{4} x

We simplify to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}   +\frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{4} x}{{ \cos}^{4} x}

Cancel common factors:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{{ \sin}x}{{ \cos}x}   +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}

This finally gives:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

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Write an algebraic expression for the word expression 11 more than e
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Step-by-step explanation:

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