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miv72 [106K]
3 years ago
8

Use geometry to evaluate the integral from 0 to 6 of the function f of x, dx for f of x equals 3 for x less than or equal to 3 a

nd equals the quantity 6 minus x for x greater than 3.
27
13.5
12
10.5

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0
Check the picture below.

\bf f(x)=
\begin{cases}
3&x\le 3\\
6-x&x\ \textgreater \ 3
\end{cases}\qquad \displaystyle \int_{0}^{6}~f(x)\cdot dx

so, you simply have a 3x3 square and a triangle with a base of 3 and a height of 3, get their areas, sum them up, it'd come out to 9 + 4.5 or 13.5.

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PLEASE HELP!!!!
Paraphin [41]

Answer:

yes

Step-by-step explanation:

1 is smaller than ten

5 0
2 years ago
Solve the system algebraically. Check your work.
Luden [163]

answer.

Answer:

x=2 and y=0 is the required result.

Step-by-step explanation:

We have been given system of equations:

5x+2y=105x+2y=10     (1)

And 3x+2y=63x+2y=6      (2)

We will use elimination method:

Multiply 1st equation by 3 and 2nd equation by 5 we get:

15x+6y=3015x+6y=30      (3)

15x+10y=3015x+10y=30      (4)

Now subtract  (4) from (3) we get:

-4y=0−4y=0

y=0y=0

Now, put y=0 in (1) equation:

5x+2(0)=105x+2(0)=10

5x=105x=10

x=2x=2

Hence, x=2 and y=0

8 0
3 years ago
A university is trying to determine what price to charge for tickets to football games. At a price of ​$ per​ ticket, attendance
Anika [276]

This question is incomplete, the complete question is;

A university is trying to determine what price to charge for tickets to football games. At a price of ​$24 per​ ticket, attendance averages 40,000 people per game. Every decrease of ​$4 adds 10,000 people to the average number. Every person at the game spends an average of ​$4 on concessions. What price per ticket should be charged in order to maximize​ revenue? How many people will attend at that​ price?

Answer:

a) price per ticket = $18

b) 55,000 will attend at that price

Step-by-step explanation:

Given that;

price of ticket = $24

so cost of ticket = 24 - x

every decrease of $4 adds 10,000 people

for $1 adds 2,500 people

Total people = 40000 + 2500x

Revenue function = people × cost + people × 4

so

R(x) = (40000 + 2500x)(24 - x) + (40000 + 2500x)4

R(x) = 960,000 - 40000x + 60000x - 2500x² + 160,000 + 10000x

R(x) = 1120000 + 30000x - 2500x²

R(x) = -2500x² + 30000x + 1120000

now for maximum revenue; R'(x) is to zero

so

R'(x) = d/dx(  -2500x² + 30000x + 1120000 ) = 0

⇒ -5000x + 30000 + 0 = 0

⇒ -5000x + 30000 = 0

⇒ 5000x = 30000

x = 30000 / 5000

x = 6

R'(X) = -5000 < 0 ⇒ MAXIMUM

∴ Revenue is maximum at x = 6

so cost of ticket ;

price per ticket = (24 - x) = 24 - 6 = $18

so price per ticket = $18

Number of people = 40000 + 2500x

= 40000 + (2500 × 6)

= 40000 + 15,000

= 55,000

Therefore, 55,000 will attend at that price

8 0
2 years ago
20 = 4x+ 6 is equivalent to the equation 24 = 4x + 10
Kruka [31]

Answer:

Addition Property

Step-by-step explanation:

Added 4 on both sides to equate the solution

5 0
2 years ago
Read 2 more answers
What is the remainder?
Alenkasestr [34]

Answer:

b

Step-by-step explanation:

I did that

4 0
3 years ago
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