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Sergio039 [100]
3 years ago
8

PLZ HELP!!! Plz answer fast if possible.

Mathematics
1 answer:
wlad13 [49]3 years ago
6 0

Answer:

For the first one:

yes

constant rate of 4 inches of perimeter/per inch of side length

For the second:

no

not a constant rate

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$21.6 in one hour

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What equation is equivalent to the equation 9x - 13 = 4x + 32
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I need help!! This is getting a little harder than I expected
MAXImum [283]

Length of the side = 9 cm

Diagonal = 9\sqrt{2} cm

Solution:

Area of the square = 81 square centimeters

In square all sides are equal.

Area of the square = side × side

Side × side = 81

Side² = 9²    (∵81 = 9²)

Taking square root on both sides, we get

Side = 9 cm

Length of the side = 9 cm

To find the length of the diagonal:

In square all the angles are right angle.

Diagonal splits the square into two right angle triangle.

Using Pythagoras theorem,

<em>In right triangle, square of the hypotenuse is equal to the sum of the square of the other two sides.</em>

Here, diagonal is the hypotenuse.

\text{Diagonal}^2=9^2+9^2

\text{Diagonal}^2=81+81

\text{Diagonal}^2=2\times 81

Taking square root on both side,

Diagonal = 9\sqrt{2} cm

6 0
3 years ago
Describe how to transform:
Anna71 [15]

Answer:

x^\frac{35}{6}

Step-by-step explanation:

The expression to transform is:

(\sqrt[6]{x^5})^7

Let's work first on the inside of the parenthesis.

Recall that the n-root of an expression can be written as a fractional exponent of the expression as follows:

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Therefore \sqrt[6]{a} = a^{\frac{1}{6}}

Now let's replace a with x^{5} which is the algebraic form we are given inside the 6th root:

\sqrt[6]{x^5} = (x^5)^{\frac{1}{6}}

Now use the property that tells us how to proceed when we have  "exponent of an exponent":

(a^n)^m= a^{n*m}

Therefore we get:  (x^5)^{\frac{1}{6}}=x^{\frac{5}{6}}}

Finally remember that this expression was raised to the power 7, therefore:

[tex](\sqrt[6]{x^5})^7=(x^\frac{5}{6})^7=x^\frac{35}{6}[/tex]

An use again the property for the exponent of a exponent:

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