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lozanna [386]
3 years ago
10

Which linear function has a negative slope, f(x) or g(x)? ​

Mathematics
2 answers:
Anit [1.1K]3 years ago
8 0

Answer:

f(x) is negative and g(x) is positive

Step-by-step explanation:

f(x) = 4-x

Rewriting

f(x) = -x+4

We recognize this as

y= mx+b or the representation of a line with slope -1 and y intercept 4

f(x) is linear

g(x)  as we increase x by 1 we increase g(x) by 2

The slope is 2, and the y intercept is 1

y = 2x+1

Lets check a point

(2,5)

5 = 2(2)+1

5=5  so we are correct

f(x) is negative and g(x) is positive

Lera25 [3.4K]3 years ago
6 0

Answer:

f(x)

Step-by-step explanation:

f(x) = -x + 4

Slope of f(x): -1 (negative)

Slope of g(x):

Slope: (-1 - -3)/(-1 - -2)

Slope = 2/1 = 2 (positive)

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Two random samples of 40 students were drawn independently from two populations of students. Assume their aptitude tests are nor
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Answer:

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the population mean for group 1 is significantly different than the population mean for group 2.  

The 95% confidence interval is given by (0.756;7.243), since the interval not contain's the 0 we can reject the null hypothesis that the means are equal.

Step-by-step explanation:

Data given and notation

\bar X_{1}=76 represent the mean for 1  

\bar X_{2}=72 represent the mean for 2  

s_{1}=8 represent the sample standard deviation for 1  

s_{2}=6.5 represent the sample standard deviation for 2

n_{1}=40 sample size for the group 1  

n_{2}=40 sample size for the group 2  

\alpha=0.05 Significance level provided  

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the population means differs, the system of  hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}= 0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, we can apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(76-72)-0}{\sqrt{\frac{8^2}{40}+\frac{6.5^2}{40}}}}=2.454  

P value  

We need to find first the degrees of freedom given by:

df=n_1 +n_{2}-2=40+40-2=78

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p_v =2*P(t_{78}>2.454)=0.016  

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The critical value for this case can be calculated like this. \alpha=1-0.95=0.05 and \alpha/2 =0.025. The degrees of freedom are 78 so we can use this code in excel to find the critical value for the interval "=-T.INV(0.025,78)" and we got t_{\alpha/2}=1.99

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(76 -72) - 1.99\sqrt{\frac{8^2}{40}+\frac{6.5^2}{40}}}=0.756

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