Find the sum (3/7m-3+4n)+(2/7m-2m+6)

Mathematics

1 answer:

aleksley [76]4 years ago

4 0

Answer:

(5/7)m + 2n + 3

Step-by-step explanation:

Rewrite 3/7m as (3/7)m for added clarity, also 2/7m as (2/7)m.

Adding (3/7)m and (2/7)m results in (5/7)m.

Next, combine -3 and 6, which yields 3.

I expected that there'd be only one term in m in both quantities. (3/7)m - 3 + 4n does have only one term, but (2/7)m - 2m + 6) seems to have two m terms. I will assume that you actually meant (2/7)m - 2n + 6).

Combining like terms, we get (5/7)m + 3 + 4n - 2n, or

(5/7)m + 2n + 3

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