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Elenna [48]
3 years ago
15

How am I supposed to set up a problem like this: y= x-8 y= 3x

Mathematics
1 answer:
Brums [2.3K]3 years ago
5 0

Answer:

x = - 4

y = - 12

Step-by-step explanation:

x - 8 = 3x

- 8 = 3x - x

2x = - 8

x = - 4

y = 3x = 3(-4) = - 12

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Which of the following is true for f(x) = -2 sin(x) - 3?
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Step-by-step explanation:

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3 years ago
An investment pays 4.6% annual interest compounded monthly. If $3100 is
elena55 [62]

Answer:

I think it's 2566.8 if 4.6 is taken out of the account annually. I think that is what it is asking.. I'm only 13 so I'm not great at these yet but it should be right because I'm really good at math

Step-by-step explanation:

3 0
3 years ago
Find the measure of the arc or central angle indicated. Assume that lines which appear to be diameters are actual diameters.
vfiekz [6]

The measure of the Central Angle indicated is; 45°

<h3>How to find the central angle of a circle?</h3>

The central angle will be the angle subtended at the center by arc FE and arc CB.

Now, we see that angle ∠FOB = 135° and since we know that sum of angles on a straight line is 180°, then we can say that;

Central Angle = 180° - 135° = 45°

Angle subtended by Arc CD at the center is;

θ = 180 - (81 + 45)

θ = 54°

Read more about Central Angle at; brainly.com/question/17074363

#SPJ1

8 0
2 years ago
12
LenaWriter [7]

Answer:

2159.74

Step-by-step explanation:

you times 456 by 4 then you times that answer by the 1742%

4 0
3 years ago
. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an
Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when X = 59.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{59.5 - 56}{1.12}

Z = 3.1

Z = 3.1 has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0
3 years ago
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